The perimeter of a right angled triangle, with hypotenuse c=101cm and one side b=20cm, is:

Mathematics

1 answer:

crimeas [40]2 years ago

3 0

Answer:

220

Step-by-step explanation:

We need to find the 3rd side length

We already know the hypotenuse and one side, so we can use the Pythagorean formula.

101^2 = a^2 + 20^2. A is the third side, and solving for it, we find that it equals 99.

Side 1 = 101

Side 2 = 99

Side 3 = 20

101 + 99 + 20 = 220

You might be interested in

!!please help!!<br>I have an F in this class and really need to get it up!

lisov135 [29]

I may be wrong, I think I remember how to do this. A straight line has an angle of 180, so y would be 133, making the area 55571.63u. (u = whatever unit is measuring the circle.) If x = 1/20 of the area, then the red area = 2,778.5u or 2,779u. I hope this helps, but I honestly don't remember how I would find x, and I don't want you to get the question wrong.

5 0

2 years ago

The Miguel traces a circle with the radius of 25 cm like the one shown. He will color the shade section what is the area of the

Scilla [17]

Answer: The area of shaded section is 491.07 cm²

Step-by-step explanation:

Given: Radius of the circle = 25 cm

Now as shown in figure the shaded region is a quadrant.

Therefore the central angle is 90°

Now as we know

Area of sector is given by

$Area= \pi r^2 \dfrac{\theta}{360^\circ}$ where r is radius and $\theta$ is central angle

So we have

$Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area= \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area= \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2$