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Firlakuza [10]
2 years ago
13

The perimeter of a right angled triangle, with hypotenuse c=101cm and one side b=20cm, is:​

Mathematics
1 answer:
crimeas [40]2 years ago
3 0

Answer:

220

Step-by-step explanation:

We need to find the 3rd side length

We already know the hypotenuse and one side, so we can use the Pythagorean formula.

101^2 = a^2 + 20^2. A is the third side, and solving for it, we find that it equals 99.

Side 1 = 101

Side 2 = 99

Side 3 = 20

101 + 99 + 20 = 220

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A partial proof was constructed given that MNOP is a parallelogram.
Yanka [14]
A diagram of parallelogram MNOP is attached below

We have side MN || side OP and side MP || NO

Using the rule of angles in parallel lines, ∠M and ∠P are supplementary as well as ∠M and ∠N.

Since ∠M+∠P = 180° and ∠M+∠N=180°, we can conclude that ∠P and ∠N are of equal size. 

∠N and ∠O are supplementary by the rules of angles in parallel lines
∠O and ∠P are supplementary by the rules of angles in parallel lines

∠N+∠O=180° and ∠O+∠P=180°

∠N and ∠P are of equal size

we deduce further that ∠M and ∠O are of equal size

Hence, the correct statement to complete the proof is

<span>∠M ≅ ∠O; ∠N ≅ ∠P

</span>

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3 years ago
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strojnjashka [21]
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2 years ago
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For the pair of similar triangles, find the value of x.
faltersainse [42]

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Step-by-step explanation:

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2 years ago
7x+11 &gt;5x-5 Can someone helpp
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Answer:

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7 0
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