Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
(16-x²)+(4-x) or (-x²+16)+(-x+4)
Combine like terms
(-x²+20-x) or (-x²-x+20)
Volume of a cylinder of radius r and heigth h is
Here h is 15 cm and r is 6 cm.
Answer:
The Fringe of the rug is 754 cm.
Step-by-step explanation:
Given:
radius = 120 cm
We need to find the fringe of the outside rug.
Solution:
Since the rug is in the circular form.
We can say that fringe of the outside edge of the rug can be equal to circumference of the circle.
Then we will find the Circumference of the circle.
Circumference of the circle is given 2 times 'π' times radius 'r'.
framing in equation form we get;
Circumference of the circle = 
Circumference of the circle = 
Hence the Fringe of the rug is 754 cm.
Answer:
the answer is 6x.
Step-by-step explanation:
