All categories

4 years ago

Average of 57 39 76 87 91

1 answer:

7 0

Add the numbers: 57 + 39 + 76 + 87 + 91 = 350;
Divide by how many numbers (i.e. we added 5 numbers): 350 ÷ 5 = 70;
So the average is 70;

You might be interested in

What is the dimensions of a box that is 11 lnches long 8 lnches wide and 6 in high

Sergio039 [100]

First you need to multiply 11(8) = 88 then multiply 88(6) = 528 then 528/3 = 176. The answer is 176 inches

7 0

4 years ago

Find the variance of the following data. Round your answer to one decimal place. x 1 2 3 4 5 P(X=x) 0.3 0.2 0.2 0.1 0.2

Reptile [31]

The variance of a distribution is the square of the standard deviation

The variance of the data is 2.2

<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

$E(x) = \sum x* P(x)$

So, we have:

$E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2$

This gives

$E(x) = 2.7$

Next, calculate E(x^2) using:

$E(x^2) = \sum x^2* P(x)$

So, we have:

$E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2$

$E(x^2) = 9.5$

The variance is then calculated as:

$Var(x) = E(x^2) - (E(x))^2$

So, we have:

$Var(x) = 9.5 - 2.7^2$

$Var(x) = 2.21$

Approximate

$Var(x) = 2.2$

Hence, the variance of the data is 2.2

Read more about variance at:

brainly.com/question/15858152

4 0

2 years ago

A tire manufacturer is interested in testing the fuel economy for two different tread patterns. Tires of each tread type are dri

Minchanka [31]

Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).

We are given the standard deviation for the samples, hence, the t-distribution is used to solve this question.

The standard errors are given by:

$s_A = \frac{1.79}{\sqrt{18}} = 0.4219$

$s_B = \frac{1.95}{\sqrt{18}} = 0.4596$

For the distribution of differences, the mean and the standard error are given by:

$\overline{x} = \mu_A - \mu_B = 23.95 - 22.19 = 1.76$

$s = \sqrt{0.4219^2 + 0.4596^2} = 0.6239$

The interval is given by:

$\overline{x} \pm ts$

The critical value for a two-tailed 99% confidence interval with 18 + 18 - 2 = 34 df is t = 2.7284.

Then:

$\overline{x} - ts = 1.76 - 2.7284(0.6239) = 0.058$

$\overline{x} + ts = 1.76 + 2.7284(0.6239) = 3.462$

The 99% confidence interval for the difference is (0.058, 3.462).

For more on the t-distribution, you can check brainly.com/question/16162795

3 0

3 years ago

Swimming pool is 10m long, 8m wide and 4m deep. Allen wants to know the

Studentka2010 [4]

V=320
10 x 8 x 4
i think

5 0

3 years ago

Read 2 more answers

The teen shop stores sweaters in boxes there are 2 sweaters in the first box 4 sweaters in the second box 6 sweaters in the thir

Xelga [282]

Answer:32

Step-by-step explanation:

4 0

3 years ago