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elena-s [515]
3 years ago
15

What is the radian value of arccos(-3/sqrt(2))?

Mathematics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

Not defined over the real numbers

Step-by-step explanation:

Let

x = arc \cos( \frac{ - 3}{ \sqrt{2} })

This implies that:

\cos(x)  =  \frac{ - 3}{ \sqrt{2} }

This implies that:

\cos(x) =  - 2.12

The range of the cosine function is -1≤y≤1

Therefore

arc \cos( \frac{ - 3}{ \sqrt{2} })

is not defined for over the real numbers.

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Never mind i found the answer
stiks02 [169]

Answer:

okieeeeeee also thanks for the points

Step-by-step explanation:

:)))

8 0
2 years ago
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Please!!!!!!!!! help!!!! me!!!!!!!!!!
LuckyWell [14K]
Hey! the answer is 8 dimes and 4 nickels

8 dimes = 8×10
and 4 nickels = 5×4 = 20
which 20+80 = 100
and I would put (D) break into parts
hope it helps!
5 0
3 years ago
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Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
2 years ago
Towns Kand L are shown on a map.
Rom4ik [11]
I’m not sure but is it C?
4 0
1 year ago
Irene tiene una colección de 50 dvd de películas de 90 minutos de duración cada una .Si el precio de cada uno era de 11€ , ¿cuan
Rainbow [258]

To solve this problem you must apply the proccedure shown below:

1. She has a total of 50 DVDs of 90 minutes each one of them. The cost of each DVD was 11€.

2. Therefore, to calculate the total cost of the collection, you must multiply the cost of each DVD by the total number of them:

total=(11)(50)=550€

3. To calculate the total minutes of the collection, you must multiply 90 minutes by the total number of DVDs:

(90min)(50)=4500min

Therefore, the answer is: 550€ and 4500 minutes.

3 0
3 years ago
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