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3 years ago

What is the radian value of arccos(-3/sqrt(2))?

Mathematics

1 answer:

Ksju [112]3 years ago

3 0

Answer:

Not defined over the real numbers

Step-by-step explanation:

Let

$x = arc \cos( \frac{ - 3}{ \sqrt{2} })$

This implies that:

$\cos(x) = \frac{ - 3}{ \sqrt{2} }$

This implies that:

$\cos(x) = - 2.12$

The range of the cosine function is -1≤y≤1

Therefore

$arc \cos( \frac{ - 3}{ \sqrt{2} })$

is not defined for over the real numbers.

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Point E is the midpoint of ab and point f is the midpoint of CD

Lorico [155]

AB is bisected by CD (TRUE). This is True because E is the midpoint between A and B and CD passes through E

CD is bisected by AB (FALSE) CD is bisected by point F and not AB

AE = 1/2 * AB (TRUE) since E is the midpoint of AB , E divides AB into two equal halves

EF = 1/2 * ED (FALSE) The true statement would have been CF = 1/2* CD

FD = EB (FALSE) sinc we do not know if CD and AB are of the same lengths

CE + EF = ED (TRUE) since F is the midpoint the sum of CE and EF is equal to ED

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3 years ago

Read 2 more answers

What is the slope-intercept equation of the line below?

laila [671]

Answer:

There is no image.

Step-by-step explanation:

Can you add a image or something because You did not give a "line below"

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3 years ago

Please help me!!!!!!!

Pie

Answer:

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3 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

Elle placed a bucket under a leaky roof. The bucket was 310 full after 25 of an hour. How much water is leaking per hour?

kvasek [131]

Answer:

3/4 bucket

Step-by-step explanation:

Elle placed a bucket under a leaky roof. The bucket was 3/10 full after 2/5 of an hour. How much water is leaking per hour

Water leaking : time taken

Let x = amount of water leaking per hour

3/10 : 2/5 = x : 1

3/10 ÷ 2/5 = x / 1

3/10 × 5/2 = x / 1

15 / 20 = x / 1

Cross product

15 * 1 = 20 * x

15 = 20x

x = 15/20

= 3/4

3/4 bucket of water is leaking per hour

4 0

3 years ago