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elena-s [515]
3 years ago
15

What is the radian value of arccos(-3/sqrt(2))?

Mathematics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

Not defined over the real numbers

Step-by-step explanation:

Let

x = arc \cos( \frac{ - 3}{ \sqrt{2} })

This implies that:

\cos(x)  =  \frac{ - 3}{ \sqrt{2} }

This implies that:

\cos(x) =  - 2.12

The range of the cosine function is -1≤y≤1

Therefore

arc \cos( \frac{ - 3}{ \sqrt{2} })

is not defined for over the real numbers.

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Given the height of the triangle (h) = 12 inches

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