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bezimeni [28]
2 years ago
14

To eliminate the y terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad

ding the equations together?
First equation: 4x − 3y = 34

Second equation: 3x + 2y = 17
Mathematics
1 answer:
arlik [135]2 years ago
3 0

Answer:

Multiply both sides of the first equation by 2.

Multiply both sides of the second equation by 3.

Step-by-step explanation:

The y terms are

-3y

2y

The LCM of 2 and 3 is 6.

We need the y terms to add to zero.

Multiply both sides of the first equation by 2 to get -6y.

Multiply both sides of the second equation by 3 to get 6y.

Then -6y + 6y = 0 eliminating the y terms after adding the equations.

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WRITE DOWN THE FALUE OF 7
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Answer:

(I need to know where the seven is located/placed.) Please give a clear answer or attach a photo next time so everybody who sees your question will understand.

Step-by-step explanation:

Comparing the numbers 700, 70, and 7; the digit "7" has a different value depending on its place within the number.

7 - ones place

70 - tens place

700 - hundreds place

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2 it’s literally just where the line crosses on the y axis
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2 years ago
X-3.5= -3.1 I'm confused​
tangare [24]

Answer:

See Below

Step-by-step explanation:

First, isolate x. To do that add 3.5 to each side

x - 3.5 =  -3.1

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3 0
3 years ago
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Solve (16×^3-3×^2+43×-5)÷(×^2-2)
Oksana_A [137]

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

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43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

7 0
2 years ago
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