The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
Answer:
Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself
Step-by-step explanation:
Okay so you have a weigh of 8 and a diagonal of 13.
If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.
Pythagorean theroum: a^2+b^2=c^2
Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.
In this case I’m substituting a for 8.
8^2+b^2=13^2
Solve the squares
64+b^2= 169
Isolate the b
b^2=105
Now square root 105
√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.
Its been a while since I have done geometry but I think it's pretty obvious that it's ABC > DBC
Separate them first.
7+8=15
5/6+2/6=7/6
There can't be 7/6, so it becomes 1 and 1/6,
15+1+1/6=16 1/6
The answer is 16 1/6.
Answer:
The smallest solution is -6
Step-by-step explanation:
2/3 x^2 = 24
Multiply each side by 3/2
3/2 *2/3 x^2 = 24*3/2
x^2 = 36
Take the square root of each side
sqrt(x^2) = sqrt(36)
x = ±6
The smallest solution is -6
The largest solution is 6
