Answer:
10x^2 -4x +6
Step-by-step explanation:
The area of the blue square is
2* 5x^2 = 10x^2
The area of the pink square is
2 * -2x = -4x
The area of the green square is
2 *3 = 6
Add it all together
10x^2 -4x +6
Answer:
Option 1 - 19, because the number of books is 95 over 4 divided by 5 over 4
Step-by-step explanation:
Given : Samantha has a shelf that is 95 over 4 inches wide.
To find : How many books can Samantha arrange on the shelf if each book is 5 over 4 inches thick?
Solution :
The thickness of shelf =
inches
Each book thickness =
inches
Let the total number of books that could be arranged in the shelf be 'n'.

Substitute the values,




Therefore, option 1 is correct.
19, because the number of books is 95 over 4 divided by 5 over 4
Draw out a horizontal line. Place 0 at the center. Then place evenly spaced tick marks on either side of 0. Label the right side of tick marks as 1, 2, 3, ... moving from 0 and going to the right
Label the left side of tick marks -1, -2, -3, ... starting at 0 and moving left
The location -3 on the number line is exactly 3 units away from 0. We start at 0 and move to -3 by moving 3 spots to the left; or we start at -3 and move 3 units to the right to get to 0.
Therefore, the absolute value of -3 is 3
Absolute value on a number line is the distance a number is from 0
The distance is never negative
Answer:
25
Step-by-step explanation:
Check the picture below.
as you can see, the graph of the volume function comes from below goes up up up, reaches a U-turn then goes down down, U-turns again then back up to infinity.
the maximum is reached at the close up you see in the picture on the right-side.
Why we don't use a higher value from the graph since it's going to infinity?
well, "x" is constrained by the lengths of the box, specifically by the length of the smaller side, namely 5 - 2x, so whatever "x" is, it can't never zero out the smaller side, and that'd happen when x = 2.5, how so? well 5 - 2(2.5) = 0, so "x" whatever value is may be, must be less than 2.5, but more than 0, and within those constraints the maximum you see in the picture is obtained.