Answer:
The probability they have one boy and one girl = 0.50 = 50 %
Step-by-step explanation:
Here the family has two children, we need to find what is the probability they have one boy and one girl.
Probability for babies are boys = 51.3% = 0.513
Probability for babies are girls = 1 - 0.513 = 0.487
The probability they have one boy and one girl = 1 - probability that they have two boys - probability that they have two girls
The probability they have one boy and one girl = 1 - 0.513² - 0.487² = 0.499 = 0.50
The probability they have one boy and one girl = 0.50 = 50%
To solve for the confidence interval for the true average
percentage elongation, we use the z statistic. The formula for confidence
interval is given as:
Confidence interval = x ± z σ / sqrt (n)
where,
x = the sample mean = 8.63
σ = sample standard deviation = 0.79
n = number of samples = 56
From the standard distribution tables, the value of z at
95% confidence interval is:
z = 1.96
Therefore substituting the known values into the
equation:
Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)
Confidence interval = 8.63 ± 0.207
Confidence interval = 8.42, 8.84
<span> </span>
Answer: x < -2
Step-by-step explanation:
Could you send the picture so I could help please :)
