<span>Given, y^2 - 14y = -44
Add 44 to both sides of the equation
</span>y^2 - 14y + 44 = -44 + 44<span>
</span>y^2 - 14y + 44 = 0
Using the quadratic formula x = [-b ± √(b² - 4ac)]/2a
Where,
a = 1
b = -14
c = 44
x = [-b ± √(b² - 4ac)]/2a
x = [-(-14) ± √(-14² - 4(1)(44)]/2(1)
x = [14 ± √(196 - 176)]/2
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 4.472)/2 OR (14 - 4.472)/2
x = 18.472/2 OR 9.528/2
x = 9.236 OR 4.764
The solution set is {9.236, 4.764}
TO EXPRESS THE ANSWER IN RADICALS
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 2√5)/2 OR (14 - 2√5)/2
<span>x = 7+√5 OR 7-√5
</span>
The solution set is {7+√5, 7-√5}
If the average of the two integers is x, the product of the two integers is
(x-1)(x+1) = 440
x² - 1 = 440
x² = 441 = 21²
21 is the odd integer between the two even integers you seek.
The integers are 20 and 22.
Set up a table of values and plug in those values to the x and then graph the points you came up with
Answer:
A
Step-by-step explanation:
Answer:
B = 781.347
Step-by-step explanation:
Since we already have an equation just plug in terms where needed.
First, start by multiplying to get rid of the parentheses.
Now get rid of the power.
B = 781.347
Hope this helps with the problem.
