Answer:
8.73 L
Explanation:
First, you need to convert grams to moles using the molar mass.
Molar Mass (N₂): 2(14.009 g/mol)
Molar Mass (N₂): 28.018 g/mol
12.2 grams N₂ 1 mole
---------------------- x ------------------------ = 0.435 moles N₂
28.018 grams
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (torr)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (62.36 torr*L/mol*K)
-----> T = temperature (K)
After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation.
P = 1132 torr R = 62.36 torr*L/mol*K
V = ? L T = 91 °C + 273.15 = 364.15 K
n = 0.435 moles
PV = nRT
(1132 torr)V = (0.435 moles)(62.36 torr*L/mol*K)(364.15 K)
(1132 torr)V = 9888.015
V = 8.73 L
Can I know which grade are uh, according to the grade only visible to check
Answer:
-255.4 kJ
Explanation:
The free energy of a reversible reaction can be calculated by:
ΔG = (ΔG° + RTlnQ)*n
Where R is the gas constant (8.314x10⁻³ kJ/mol.K), T is the temperature in K, n is the number of moles of the products (n =1), and Q is the reaction quotient, which is calculated based on the multiplication of partial pressures by the partial pressure of the products elevated by their coefficient divide by the multiplication of the partial pressure of the reactants elevated by their coefficients.
C₂H₂(g) + 2H₂(g) ⇄ C₂H₆(g)
Q = pC₂H₆/[pC₂H₂ * (pH₂)²]
Q = 0.261/[8.58*(3.06)²]
Q = 3.2487x10⁻³
ΔG = -241.2 + 8.314x10⁻³x298*ln(3.2487x10⁻³)
ΔG = -255.4 kJ
Answer:
A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.
Answer:
Moles of carbon dioxide gas is 0.584 moles.
Mass of 0.584 moles of carbon dioxide gas is 25.7 g
Explanation:
Using ideal gas equation
PV = nRT
where,
P = Pressure of gas = 
V = Volume of gas = 30.0 L
n = number of moles of gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas = 27°C = 300.15 K
Putting values in above equation, we get:
Moles of carbon dioxide gas = 0.584 moles
Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7 g
