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Sonja [21]
3 years ago
6

You need to make an aqueous solution of 0.150 M sodium fluoride for an experiment in lab, using a 500 mL volumetric flask. How m

uch solid sodium fluoride should you add?
Chemistry
1 answer:
storchak [24]3 years ago
7 0

Answer:

Explanation:

Solution required is .15 M 500 mL sodium fluoride .

molecular weight of sodium fluoride = 42

one mole of sodium fluoride = 42 grams

No of moles contained in the solution of .15M , 500 mL solution

= .15 x 0.5 moles = .075 moles

1 mole = 42 g

.075 moles = .075 x 42 = 3.15 grams .

So mass of sodium fluoride required = 3.15 g .

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oee [108]
7.5 is the answer. You have to move the decimal 2 places to the right.
5 0
3 years ago
Write a balanced overall reaction from these unbalanced half-reactions sn and ag
loris [4]
Balance each one by adding electrons to make the charges on both sides the same:

Sn--> Sn2+ + 2 e-
Ag+ + 1 e- --> Ag

Now, you have to have the same number of electrons in the two half-reactions, so multiply the second one by 2 to get:

2 Ag+ + 2 e- --> 2 Ag

Now, just add the two half reactions together, cancelling anything that's the same on both sides:

2 Ag+ + Sn --> Sn2+ + 2 Ag

And you're done.
8 0
3 years ago
What mass of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 110.0 kPa and a temperature of 25 C?
likoan [24]

Answer:

40.94 g

Explanation:

Given data:

Mass of NO₂ = ?

Volume = 20.0 L

Pressure = 110.0 Pka

Temperature = 25°C

Solution:

Pressure = 110.0 KPa (110/101 = 1.1 atm)

Temperature = 25°C (25+273 = 298.15 K)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1.1 atm × 20.0 L / 0.0821 atm.L/ mol.K ×298.15 K

n = 22 / 24.5 /mol

n= 0.89 mol

Mass of NO₂:

Mass = number of moles × molar mass

Mass = 0.89 mol × 46 g/mol

Mass = 40.94 g

3 0
3 years ago
A 0.708 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
ollegr [7]

Answer:

The metal has a molar mass of 65.37 g/mol

Explanation:

Step 1: Data given

Mass of the metal = 0.708 grams

Volume of hydrogen = 275 mL = 0.275 L

Atmospheric pressure = 1.0079 bar = 0.9947 atm

Temperature = 25°C

Vapor pressure of water at 25 °C = 0.03167 bar = 0.03126 atm

Step 2: The balanced equation

M(s) + H2SO4(aq) ⟶ MSO4 (aq) + H2(g)

Step 3: Calculate pH2

Atmospheric pressure = vapor pressure of water + pressure of H2

0.9947 atm = 0.03126 atm + pressure of H2

Pressure of H2 = 0.9947 - 0.03126

Pressure of H2 = 0.96344 atm

Step 4: Calculate moles of H2

p*V=n*R*T

⇒ with p = The pressure of H2 = 0.96344 atm

⇒ with V = the volume of H2 = 0.275 L

⇒ with n = the number of moles H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 25°C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.96344 * 0.275)/(0.08206*298)

n = 0.01083 moles

Step 5: Calculate moles of M

For 1 mole of H2 produced, we need 1 mole M

For 0.0108 moles of H2 we need 0.01083 moles of M

Step 6: Calculate molar mass of M

Molar mass M = Mass M / moles M

Molar mass M = 0.708 grams / 0.01083 moles

Molar mass M = 65.37 g/mol

The metal has a molar mass of 65.37 g/mol

5 0
3 years ago
A teacher rubbed a match against a piece of sandpaper. The match started to burn. Which statement best describes the energy chan
timurjin [86]

Answer:

C

Explanation:

The chemical energy stored in the match changed to thermal energy and light energy.

4 0
2 years ago
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