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3 years ago

How does the difference in the mass of the ball affects the changes in the distance of the object

Chemistry

1 answer:

beks73 [17]3 years ago

4 0

Answer:

In very simple words ,

As the weight increases the gravitational force acting on the ball increases and thus it effects the change in the distance of the ball as the ball will fall very close to its initial distance if it has more mass and shall go far if the mass is less .

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In a reaction 4 NH3 + 5 O2 → 4 NO + 6 H2O, 1 mole of ammonia reacts with 2 moles of oxygen. Which of these is correct after the

Vsevolod [243]

Answer:

<em><u>Option B) All the ammonia is consumed</u></em>

Explanation:

<u>1. Balanced chemical equation (given):</u>

$4NH_3+5O_2\rightarrow 4NO+6H_2O$

<u>2. Theoretical mole ratios:</u>

$4molNH_3:5molO_2:4molNO:6H_2O$

<u>3. Limiting reactant:</u>

When 1 mole of ammonia is combined with 2 moles of oxygen, the mole ratio is:

$1molNH_3:2molO_2$

Hence, one of the reactants will be completely consumed (the limiting reactant) and, after completion, an excess of the other will remain unreacted.

You need to compare the the actual ratio with the theoretical ratio.

4/5 > 1/2

Hence, NH₃ is in less proportion with respect to oxygen than what is theoretically needed, and the former is the limiting reactant.

Therefore, the 1 mole (all) of ammonia will be consumed, while some oxygen will remain as excess. This is described by the option B) All the ammonia is consumed.

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<u>4. Analyze the other options:</u>

The amount of oxygen that will react is:

$1molNH_3\times5molO_2/4molNH3=5/4molO_2$

And the amount that will remain is:

$2molO_2-4/5molO_2=6/5molO_2$

Neither option A) nor C) describe that situation.

The amount of water produced is:

$1molNH_3\times 6molH_2O/4molNH_3=1.5molH_2O$ , which is not described by the option D).

Hence, the correct answer is the option B) All the ammonia is consumed.

6 0

3 years ago

Why were microscopes essential in the discovery of cells

fredd [130]

Answer: hey nice to see you again, the answer is B. Microscopes allowed scientists to see the cells.

Explanation:

8 0

3 years ago

Read 2 more answers

Write the cell notation for the voltaic cell that incorporates each of the following redox reactions:(a) Al(s) + Cr³⁺(aq) → Al³⁺

Sladkaya [172]

The cell notation for the given voltaic cell is as follows

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

<h3>What is a voltaic cell?</h3>

The device in which electrons are transferred through an external source is known as a voltaic cell.

The electron flow of a Voltaic cell allows redox reactions to produce energy in the form of electricity.

It converts the energy of spontaneous redox reaction into electrical energy

An anode, a cathode, and a salt bridge are all parts of a voltaic cell's setup. The salt bridge serves to neutralize the system.

To write the cell notation, identify the oxidation and reduction reactions.

At the anode, oxidation takes place

$Al(s) \longrightarrow Al^{3+} (aq) + 3e^-$

At the cathode, reduction takes place

$Cr^{3+} (aq) + 3e^- \longrightarrow Cr(s)$

While writing cell notation, the anode is written on the left, and the cathode is written on the right

A single vertical line differentiates between the phases and a double vertical line represents the salt bridge.

Now, write the cell notation of the given Voltaic cell

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

Learn more about Voltaic cells:

brainly.com/question/14312871

#SPJ4

7 0

2 years ago

Please answer quickly

Stolb23 [73]

Inherited it from his grandfather

8 0

2 years ago

If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol

Lelu [443]

<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

$P_{1}V_{1}=P_{2}V_{2}$