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tigry1 [53]
3 years ago
8

10 2/3 x 6 1/4 simplify or reduce

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

66 2/3

Step-by-step explanation:

10 2/3=32/3 as a improper fraction(multiply 10 by denominator and add to numerator to get numerator of improper fraction)

6 1/4=25/4 as a improper fraction)

32/3*25/4=32*25/3*4=800/12=66 2/3

Marta_Voda [28]3 years ago
7 0

Step-by-step explanation:

10 \frac{2}{3}  \times 6 \frac{1}{4}  \\  \\  =  \frac{10 \times 3 + 2}{3}  \times  \frac{6 \times 4 + 1}{4} \\  \\  =  \frac{30+ 2}{3}   \times  \frac{24 + 1}{4}  \\  \\  =  \frac{32}{3}  \times  \frac{25}{4}  \\  \\  =  \frac{8}{3}  \times  \frac{25}{1}  \\  \\  =  \frac{200}{3}  \\   \\  = 66 \frac{2}{3}

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a single die is rolled one time. Find the probability of rolling a number greater than 4 or less than 3.
Fynjy0 [20]
Answer

The probability of rolling a number of 2 is 1/6 (16.667%)

The probability of rolling a number of 3 is 2/6 (33.33%)

The probability of rolling a number 4 is 3/6 (50%)

The probability of rolling a number 5 is 4/6 (66.667%)

Explanation:
I’m not sure what you were trying to look for. So I put the probability for numbers 2,3,4, and 5. Your welcome, have a great day/night!.
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36

Step-by-step explanation:

6(4+2)

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3 years ago
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posledela

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Step-by-step explanation:

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3 years ago
Calculate this reflection of the triangle:
Mice21 [21]

Answer:

a = 3, b = 0, c = 0, d = -2

Step-by-step explanation:

<em>To find the reflection Multiply the matrices</em>

∵ The dimension of the first matrix is 2 × 2

∵ The dimension of the second matrix is 2 × 3

<em>1. Multiply the first row of the 1st matrix by each column in the second matrix add the products of each column to get the first row in the 3rd matrix.</em>

2. Multiply the second row of the 1st matrix by each column in the second matrix add the products of each column to get the second row of the 3rd matrix

\left[\begin{array}{ccc}1&0\\0&-1\end{array}\right]  × \left[\begin{array}{ccc}0&3&0\\0&0&2\end{array}\right]  = \left[\begin{array}{ccc}(1*0+0*0)&(1*3+0*0)&(1*0+0*2)\\(0*0+-1*0)&(0*3+-1*0)&(0*0+-1*2)\end{array}\right]=\left[\begin{array}{ccc}0&3&0\\0&0&-2\end{array}\right]

Compare the elements in the answer with the third matrix to find the values of a, b, c, and d

∴ a = 3

∴ b = 0

∴ c = 0

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7 0
3 years ago
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