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Mariana [72]
2 years ago
6

If there is a maximum of 4,000 hours of labor available per month and 300 ping-pong balls (x1) or 125 wiffle balls (x2) can be p

roduced per hour of labor, which of the following constraints reflects this situation?
a. 300x1 + 125x2 > = 4,000
b. 300x1 + 125x2 < = 4,000
c. 425(x1 + x2) < = 4,000
d. 300x1 + 125x2 = 4,000
Mathematics
1 answer:
andrey2020 [161]2 years ago
6 0

Answer:

b. 300x1 + 125x2 < = 4,000

Step-by-step explanation:

Maximum of 4,000 hours

This means that the the total amount of labor has to be of at most 4,000, that is:

T \leq 4000

300 ping-pong balls (x1) or 125 wiffle balls (x2) can be produced per hour of labor

The total amount of labor is:

T = 300x1 + 125x2

Uniting the two equations:

T \leq 4000

300x1 + 125x2 \leq 4000

And thus the correct answer is given by option b.

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Point on the circle = (2,-4).

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Solution:

Distance between two points is

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Distance between the center (-1,0) and the point on the circle (2,-4) is the radius of the circle.

r=\sqrt{(2-(-1))^2+(-4-0)^2}

r=\sqrt{(2+1)^2+(-4)^2}

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On further simplification, we get

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r=\sqrt{25}

r=5

Now, the equation of the circle is

(x-h)^2+(y-k)^2=r^2

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The radius of the circle is 5 and the center is at (-1,0), so the equation of the circle is

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(x+1)^2+y^2=25

Therefore, the first option is correct, i.e., (x+1)^2+y^2=25.

3 0
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