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dolphi86 [110]
1 year ago
9

the sum of three numbers is 78. the third number is 3 times the first. the first number is 7 more than the second. what are the

numbers?
Mathematics
2 answers:
Lena [83]1 year ago
4 0

Answer:

17

Step-by-step explanation:

x+3x+x-7=78

5x-7=78

5x=78+7

5x=85

x=85/5

x=17

makkiz [27]1 year ago
4 0

<u>Answer:</u>

The three numbers are 17, 10 and 51.

<u>Step-by-step explanation:</u>

Let the first, second, and third numbers be x, y, and z respectively.

• From the question, we know:

sum of the numbers is 78.

∴ x + y + z = 78   ----------(1st equation)

Let's express both x and  z in terms of \bf y :

• We know that:

the third number is 3 times the first.

∴ z = 3x

⇒ x = \frac{z}{3}     ----------(2nd equation)

• We also know that:

the first number is 7 more than the second.

∴ \boxed{x = 7 + y}

Substituting  x = \frac{z}{3}  (from 2nd equation)

⇒ \frac{z}{3} = 7 + y

⇒ \boxed{z = 21 + 3y}

• We can now substitute  x = 7 + y  and  z = 21 + 3y  into the first equation:

x + y + z = 78

⇒ (7 + y) + y + (21 + 3y) = 78

⇒ 5y + 28 = 78

⇒ 5y = 50

⇒ y = \bf 10

∴ x = 7 + 10\\

⇒ x = \bf 17

z = 21 + 3(10)

⇒ z = \bf 51

∴ The three numbers are 17, 10 and 51.

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