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2 years ago

13

How many kilometers are equal to 750 meters?

1 answer:

Alexandra [31]2 years ago

5 0

Answer:

$0.75$

Step-by-step explanation:

750metres÷1000

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The angle of depression from the top of the tree to the tip of the shadow is 25°. Find the height of the tree to the nearest ten

saul85 [17]

No answer is possible using only the information given in the question.
In addition to the angle of depression, we need either one of these:
-- the length of the tree's shadow on the ground
-- the slant distance direct from the tip of the shadow to the top of the tree.

I'm going out on a limb and guessing that on the page, next to that much of the
question, was a picture of the tree, with one of these additional items labeled.
There's an important reason why the publisher decided to go to the effort and
expense of printing the picture right there. I leave you to ponder the reason.

6 0

2 years ago

Reduce 6 over 12 to the lowest terms

erma4kov [3.2K]

Answer:

1/2

Step-by-step explanation:

6/12 =

(2 × 3)/(22 × 3) =

((2 × 3) ÷ (2 × 3)) / ((22 × 3) ÷ (2 × 3)) =

1/2

7 0

3 years ago

Read 2 more answers

The sum of a number and 12 is -3. What is the number?

Anna35 [415]

Answer:

-9?

Step-by-step explanation:

6 0

2 years ago

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The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

The edges of a cube increase at a rate of 2 cm divided by s. How fast is the volume changing when the length of each edge is 40

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

Let the edge of the cube be a .

Given

$\frac{da}{dt} = 2 cm/s$

Volume V = a³

$\frac{dV}{dt} = 3a^ 2\frac{da}{dt}$

= 3a² x 2

= 6a²

If a = 40 cm

$\frac{dV}{dt} = 6 \times 40\times40$

= 9600 cm³/s .

5 0

2 years ago