Answer:
what if my moms a chicken?
Step-by-step explanation:
asking for a friend
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
3b) 4 tickets/$16 = 0.25 tickets/$1
4a & 4b) You didn’t provide a photo of the problems that I need to solve them
4c) ($4/1 ticket) x (1000 tickets) = $4000
1 and 24
2 and 12
3 and 8
4 and 6
Answer:
p=1
Step-by-step explanation:
2/5 + p = 4/5 + 3/5p
Multiply each side by 5 to clear the fractions
5(2/5 + p) = 5(4/5 + 3/5p)
2 +5p = 4 + 3p
Subtract 3p from each side
2+5p-3p = 4+3p-3p
2+2p = 4
Subtract 2 from each side
2+2p -2 = 4-2
2p =2
Divide by 2
2p/2 = 2/2
p=1