Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be 
Let weight of each okapi be 
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em>
</em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em>
</em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:
Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:
Each okapi weigh 290 kg
Answer: Slope = 5/4
y-intercept = 2
Step-by-step explanation:
We have the table:
Months, m Plant height in inches, n
0 2
2 4.5
4 7
6 9.5
We want a linear relationship to represent this table.
A linear relationship can be written as:
y = a*x + b
where a is the slope and b is the y-axis intercept.
For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:
a = (y2 - y1)/(x2 - x1).
In this case we can select any pair of points, for example, i will choose the first two:
(0, 2) and (2, 4.5)
Then the slope is:
a = (4.5 - 2)/(2 - 0) = (2.5/2) = 1.25 = 5/4
Then our line can be written as:
y = (5/4)*x + b
To find the value of b, we can replace the values of any of the points in the equation, for example, i will use the point (0, 2) or x = 0, y = 2.
2 = (5/4)*0 + b
2 = b
Then our equation is:
y = (5/4)*x + 2.
Slope = 5/4
y-intercept = 2
Let U = {5, 10, 15, 20, 25, 30, 35, 40, 45, 50} A = {5, 10, 15, 20, 25} B = {25, 30, 35, 40, 45} C = {10, 20, 30, 40, 50} Find A
Dima020 [189]
Answer:
A∪B = {5, 10, 15, 20, 25, 30, 35, 40, 45}
Step-by-step explanation:
A = {5, 10, 15, 20, 25}
B = {25, 30, 35, 40, 45}
Find A∪B
There are 5 elements in set A
There are 5 elements in set B
A∪B is the combination of all the elements in set A and set B without repeating any
A∪B = {5, 10, 15, 20, 25, 30, 35, 40, 45}
A∪B has 9 elements in it
A ⋂ B = {25}
