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3 years ago

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I have two questions, Write an expression that shows how to multiply 7×256 using expanded form and the Distributive property. An

d,Lily uses the expression (8×3,000)+(8×200)+(8×9) to help solve a multiplication problem.What is Lily's multiplication problem? PLS HELP!!!!!!!

1 answer:

Sidana [21]3 years ago

7 0

A.
7x256
7x(200+50+6)
7x200 + 7x50 + 7x6
7x200 + 7x50 + 7x6 is the expression of 7x256.
b.
(8x3000)+(8x200)+(8x9)
8x3000+200+9
8x3209
Lily's multiplication problem is 8x3209.

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20 pts to whoever helps!!

VladimirAG [237]

<h3>Answer: B) 31.348</h3>

======================================

Work Shown:

We will never use the alpha = 0.05 value when computing the test statistic. So we can ignore alpha for this particular problem.

-------

n = 40 is the sample size.

s = 2.6 is the sample standard deviation

$\sigma$ = sigma = 2.9 is the population standard deviation (ie the claimed standard deviation for all the pay phones)

Test Statistic for chi-square

$\chi^2 = \frac{(n-1)*s^2}{\sigma^2}\\\\\chi^2 = \frac{(40-1)*(2.6)^2}{(2.9)^2}\\\\\chi^2 = \frac{39*6.76}{8.41}\\\\\chi^2 = \frac{263.64}{8.41}\\\\\chi^2 \approx 31.3483947681332\\\\\chi^2 \approx 31.348\\\\$

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2 years ago

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109⁰+118⁰+44⁰=× can you please help

Paha777 [63]

Answer:

x = 271 degrees

Step-by-step explanation:

6 0

2 years ago

A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the

iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

$Event\ 1 = \{1,2,3,4,5,6\}$

Next, we list out the sample space of F

$Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\$

$6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}$

In (1): the sample space of E is:

$E = \{1\}$

So:

$P(E) = \frac{n(E)}{n(Event\ 1)}$

$P(E) = \frac{1}{6}$

In (2): the sample space of F is:

$F = \{5,5,5,5\}$

So:

$P(F) = \frac{n(F)}{n(Event\ 2)}$

$P(F) =\frac{4}{36}$

$P(F) =\frac{1}{9}$

For E and F to be independent:

$P(E\ and\ F) = P(E) * P(F)$

Substitute values for P(E) and P(F)

This gives:

$P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}$

$P(E\ and\ F) = \frac{1}{54}$

However, the actual value of P(E and F) is 0.

This is so because $E = \{1\}$ and $F = \{5,5,5,5\}$ have 0 common elements:

So:

$P(E\ and\ F) = 0$

Compare $P(E\ and\ F) = \frac{1}{54}$ and $P(E\ and\ F) = 0$ .

These values are not equal.

Hence: the two events are not independent

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2 years ago

Expand and simplify (x+5)(x-2)

salantis [7]

Answer:

${x}^{2} - x - 12 = (x + 3)(x - 4)$

${x}^{2} + 3x + 2 = (x + 2)(x + 1)$

${x}^{2} + 3x - 10 = (x + 5)(x - 2)$

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

${x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12$

${x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2$

${x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10$

I am joyous to assist you anytime.

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2 years ago

ST has endpoints Y(-2, -4) and T (6, 8). Find the coordinates of the midpoint of ST

storchak [24]

add up the X values and y values and divide by two

X=(-2+6)/2=2

Y=(-4=8)/2=2

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2 years ago

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