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balandron [24]
3 years ago
10

I have two questions, Write an expression that shows how to multiply 7×256 using expanded form and the Distributive property. An

d,Lily uses the expression (8×3,000)+(8×200)+(8×9) to help solve a multiplication problem.What is Lily's multiplication problem? PLS HELP!!!!!!!
Mathematics
1 answer:
Sidana [21]3 years ago
7 0
A.
7x256
7x(200+50+6)
7x200 + 7x50 + 7x6
7x200 + 7x50 + 7x6 is the expression of 7x256.
b. 
(8x3000)+(8x200)+(8x9)
8x3000+200+9
8x3209
Lily's multiplication problem is 8x3209.





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20 pts to whoever helps!!
VladimirAG [237]
<h3>Answer: B) 31.348</h3>

======================================

Work Shown:

We will never use the alpha = 0.05 value when computing the test statistic. So we can ignore alpha for this particular problem.

-------

n = 40 is the sample size.

s = 2.6 is the sample standard deviation

\sigma = sigma = 2.9 is the population standard deviation (ie the claimed standard deviation for all the pay phones)

Test Statistic for chi-square

\chi^2 = \frac{(n-1)*s^2}{\sigma^2}\\\\\chi^2 = \frac{(40-1)*(2.6)^2}{(2.9)^2}\\\\\chi^2 = \frac{39*6.76}{8.41}\\\\\chi^2 = \frac{263.64}{8.41}\\\\\chi^2 \approx 31.3483947681332\\\\\chi^2 \approx 31.348\\\\

7 0
2 years ago
Read 2 more answers
109⁰+118⁰+44⁰=× can you please help​
Paha777 [63]

Answer:

x = 271 degrees

Step-by-step explanation:

6 0
2 years ago
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

6 0
2 years ago
Expand and simplify (x+5)(x-2)
salantis [7]

Answer:

{x}^{2} - x - 12 = (x + 3)(x - 4)

{x}^{2} + 3x + 2 = (x + 2)(x + 1)

{x}^{2} + 3x - 10 = (x + 5)(x - 2)

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

{x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12

{x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2

{x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10

I am joyous to assist you anytime.

8 0
2 years ago
ST has endpoints Y(-2, -4) and T (6, 8). Find the coordinates of the midpoint of ST
storchak [24]

add up the X values and y values and divide by two

X=(-2+6)/2=2

Y=(-4=8)/2=2

5 0
2 years ago
Read 2 more answers
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