vertical asymptote at x = 2 and x = - 2
horizontal asymptote at y = 2
the function → ± ∞ at x = 2 and x = - 2 ⇒ vertical asymptotes
As x → ± ∞, y → -2 ⇒ y = -2 is a horizontal asymptote
Answer:
0 ≠ 110
No solution
Step-by-step explanation:
Solve by Addition/Elimination
12y = 17 − 9x and −4y − 3x = 31
Reorder 17 and −9x. 12y = −9x + 17
−4y − 3x = 31
Add 9x to both sides of the equation.
12y + 9x = 17
−4y − 3x = 31
Reorder the polynomial.
9x + 12y = 17
−4y − 3x = 31
Reorder the polynomial.
9x + 12y = 17
−3x − 4y = 31 9x + 12y = 17
Multiply each equation by the value that makes the coefficients of x opposite.
9x + 12y = 17
(3) ⋅ (−3x − 4y) = (3) (31)
Simplify (3) ⋅ (−3x − 4y).
Apply the distributive property.
9x + 12y = 17
3 (−3x) + 3 (−4y) = (3) (31)
Multiply −3 by 3. 9x + 12y = 17
−9x + 3 (−4y) = (3) (31)
Multiply −4 by 3. 9x + 12y = 17
−9x − 12y = (3) (31)
Multiply 3 by 31. 9x + 12y = 17
−9x − 12y = 93
Add the two equations together to eliminate x from the system.
9x+12y=17
+−9x−12y=93
0=110
Since 0 ≠ 110, there are no solutions. No solution
Answer:
The point of intersection is 
Step-by-step explanation:
f(x) = 2x^2 + 3x - 3 and g(x) = - x^2
By equating them
2x^2 + 3x - 3 = -x^2
3x^2 + 3 x - 3 = 0
x^2 + x - 1 = 0
Answer:
refer to the picture for step by step answer
hope it helps
12.25m^2 because you’re finding area
A=l•W
A=3.5•3.5
A=12.25
