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prisoha [69]
3 years ago
8

if a square + b square + c square minus ab minus bc minus ca equals to zero, prove that A equals to B equal to C

Mathematics
1 answer:
lawyer [7]3 years ago
8 0
A^2 + b^2 + c^2  - ab - bc - ca = 0
a.a + b.b + c.c = a.b + b.c + c.a

equating  term by term:- 
a = b
b = c 
c = a

Therefore a = b = c 
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Answer:

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

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Step-by-step explanation:

Given the relation: t{(−1,0),(7,0),(−1,9),(−6,−9)}

In the ordered pairs:

  • The domain is the set of all "x" values
  • The range is set of all "y" values
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Domain: {-6, -1, 7}

Range: {-9, 0, 9}

Next, we determine whether the relation is a function.

For a relation to be a function, each x must correspond with only one y value.

However, as is observed in the mapping attached below:

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  • f(-1)=9

The x-value (-1) corresponds to two y-values (0 and 9)

Therefore, the relation is not a function.

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