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Yakvenalex [24]
3 years ago
11

Determine the values of c so that the following functions represent joint probability distributions of the random variables X an

d Y : (a) f(x,y)=cxy, forx =1 ,2,3; y =1 ,2,3; (b) f(x,y)=c|x−y|, forx = −2,0,2; y = −2,3.

Mathematics
2 answers:
Xelga [282]3 years ago
8 0

Answer:

A: f(x,y)= 1/36xy;X=1,2,3; y=1,2,3

B: c=1/15

Step-by-step explanation:

Attached is the complete solving.

Anna11 [10]3 years ago
7 0

Answer:

The joint probility density will be c = 1/36

The joint probability distribution will be c = 1/15

Step-by-step explanation:

For step by step explanation see the pucture attached

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120 books inceased by 55%
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Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin
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Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

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We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}

y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}

y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}

It is linear differential equation because  this equation is of the form

y'+P(x)y=g(x)

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y'+P(x)y=g(x)

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Homogeneous equation

\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}

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Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

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