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Sophie [7]
2 years ago
8

What should a driver do when he/she gets to a speed hump? a maintain current speed. b accelerate. c brake. d reduce speed to sug

gested limit.
Physics
1 answer:
Llana [10]2 years ago
6 0

It is usually best to reduce speed to suggested limit when  a driver gets to a speed hump and is denoted as option D.

<h3>What is Deceleration?</h3>

This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.

Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.

Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.

This therefore the reason why reducing speed to suggested limit is the most appropriate choice.

Read more about Speed hump here brainly.com/question/9213903

#SPJ1

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When throwing a ball upwards, the velocity is positive, and the acceleration is negative. True of False?
Setler79 [48]

Answer:

The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.

Explanation:

3 0
3 years ago
A balloon contains 0.04m3 of air at a pressure of 1.20 x 105Pa. Calculate the pressure required to reduce its volume to 0.025m3
sdas [7]

Answer:

you can simply answer p1v1=p2v2 p2 = p1v1÷ p2 then inter what given in the formula you get it pl=1.20x 105pa vl= 0.40m3 v2=0.025m3

4 0
3 years ago
A 1000.0 kg truck accelerates from 20.0 m/s to 25.0 m/s over a distance of 300.0 m. What is the average net force on the truck?
choli [55]

Answer:

The average net force on the truck is 375 Newtons.

Explanation:

Using Newton's 3rd equation of motion, we have :

v^{2} - u^{2} = 2×a×s

where, v = final velocity = 25 m/s

u = initial velocity = 20 m/s

a = acceleration

s = distance traveled = 300 m

Using these values in the above equation, we get acceleration = 0.375 m/s^{2}

Using Newton's second law, we have:

F=m×a

where m = mass = 1000 kg

a= acceleration = 0.375 m/s^{2}

Putting values we have F=375 N

3 0
3 years ago
What is a unit of acceleration?<br> a. m/s<br> b. m/s2<br> c. m2/s<br> d. kg-m/s2
Basile [38]
A). m/s ... meters per second. 
                 That's a speed.

b). m/s² ... (meters per second) per second. 
                   Acceleration
.

c). m²/s ... square meters per second.
                 Rate of change of area.
                 Meaningless unit, unless you happen to be
                     a painter of houses or a mower of lawns.

d). kg-m/s² ... (mass) x (an acceleration). 
                      This is a unit of force.  
                       In fact, it's the definition of "newton".
3 0
3 years ago
A single-turn circular loop of wire of radius 65 mm lies in a plane perpendicular to a spatially uniform magnetic field. During
BabaBlast [244]

Answer:

Explanation:

change in flux = no of turns x area of loop x change in magnetic field

= 1 x π 65² x 10⁻⁶ x ( 650 - 350 ) x 10⁻³

= 3.9 x 10⁻³ weber .

rate of change of flux  = change of flux / time

= 3.9 x 10⁻³ / .10

= 39 x 10⁻³ V

= 39 mV .

Since the magnetic flux is directed outside page and it is increasing , induced current will be clockwise so that magnetic field is produced in opposite direction to reduce it , as per Lenz's law.

5 0
3 years ago
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