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3 years ago

TRUE OR FALSE 2 QUESTIONS NEED HELP ASAP THX :) LOTS OF POINTS :>

Physics

1 answer:

Liula [17]3 years ago

3 0

Answer: Both False

Explanation:

Our Milky Way Galaxy is a spiral galaxy. Some spiral galaxies are what we call "barred spirals" because the central bulge looks elongated

Irregualuar glaxyices are all over the place

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A block of 7.80 kg kept on an inclined plane just begins to slide at an angle of inclination of 35.0°. Once it has been set into

Bas_tet [7]

Answer:

The answer is....i am sorry idk

8 0

4 years ago

In the amusement park ride known as Magic Mountain Superman, powerful magnets accelerate a car and its riders from rest to 43.4

Anton [14]

Answer:

Average net force, F = 15157.15 N

Explanation:

It is given that,

The mass of the car and riders is, $m=3\times 10^3\ kg$

Initial speed of the car, u = 0

Final speed of the car, v = 43.4 m/s

Time, t = 8.59 seconds

We need to find the average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :

F = m a

$F=m(\dfrac{v-u}{t})$

$F=3\times 10^3\ kg\times (\dfrac{43.4\ m/s-0}{8.59\ s})$

F = 15157.15 N

So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.

5 0

3 years ago

Approximately how much energy is contained in 1 g of matter?

aleksley [76]

Option (B) is correct.Energy contained in one gram of matter=9 x 10¹³ J

Explanation:

mass= 1 g= 0.001 kg

c= velocity of light= 3 x 10⁸ m/s

The mass energy equivalence equation is given by

E = m C²

E= (0.001)(3 x 10⁸)²

E=9 x 10¹³ J

Thus energy contained in one gram of matter=9 x 10¹³ J

7 0

3 years ago

Consider the circular motion of a positively charged particle in the plane of this paper, due to a constant magnetic field B~ wh

barxatty [35]

Answer:

the direction of the particle is anti clockwise.

Explanation:

We know that;

- It's a positive particle

- That it's moving in a circle in a magnetic field

- We know the direction of the magnetic field

We can deduce the direction of the magnetic force because it is moving in a circle.

So the force is pointing to the centre of the circle and that's what is keeping it in that circular motion.

Since we know the direction of the magnetic field and force, we can use right hand rule to figure out the direction of the particle since the particle is positive.

Using right hand rule, the thumb which is the particle is pointing anticlockwise. So the direction of the particle is anti clockwise.

3 0

3 years ago

One end of a horizontal spring with force constant 76.0 N/m is attached to a vertical post. A 5.00-kg can of beans is attached t

Jobisdone [24]

Answer:

a. The speed is 2.39 m/s

b. The acceleration of the block is 10.2 $\frac{m}{s^{2} }$

Explanation:

First, we have to do the energy balance where we consider two states, the first where the spring remains still and the second when it is stretched 0.400m:

$K_{1} +U_{1}+W_{ext}=K_{2}+U_{2}\\K_{1}=0\\U_{1}=\frac{1}{2} kx^{2} _{1} =0\\W_{ext}=F$ Δx= $(0.400m)\\$

W_{ext}=20.4 Nm

$U_{2} =\frac{1}{2} kx^{2} =\frac{1}{2} (76.0N/m)0.400^{2}=6.08Nm\\k_{2} =\frac{1}{2}mv^{2} _{2} \\\frac{1}{2} mv^{2} _{2}=W_{ext}-U_{2}\\v_{2}=\sqrt{\frac{W_{ext}-U_{2}}{m} } \\v_{2}=\sqrt{\frac{20.4Nm-6.08Nm}{2.5kg} } \\v_{2}=2.39 \frac{m}{s}$

To determine, the acceleration we solve the following equation for a:

$F=ma\\a=\frac{F}{m} =\frac{51.0N}{5.00kg}\\a=10.2\frac{m}{s^{2} }$

8 0

4 years ago