The complete options are;
A. The average kinetic energy of their particles is the same.
B. The total kinetic energy of their particles is equal.
C. Heat flows from the larger object to the smaller object.
D. Heat flows from the object with higher potential energy to the object with lower potential energy.
Answer:
Explanation:
From the relationship between average kinetic energy and temperature, we have the formula;
E_k = (3/2)kT
Where;
k is a constant known as boltzmann constant.
T is known as temperature
We can see that at the same temperature (T), kinetic energy will remain the same because from the formula, E_k depends km only the temperature.
Thus, average kinetic energy of their particles saying that.
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1. U = Q + W
U = -500 + 1000
U = 500 J
2. The first law of thermodynamic is about the law of conservation of energy where energy in should be equal to energy out.
3. It is the windmill that does not transform energy from heat to mechanical instead it is the transforms the opposite.
4. In a heat engine, work is used to transfer thermal energy from a hot reservoir to a cold one.
5. 5.00 × 10^4 J - 2.00 × 10^4 J = 3.00 × 10^4 J
6. To increase the work done, we raise the temperature of the cold reservoir.
Answer:
I think it's D) Guess why? I searched it up!
Answer:
24,000 m
Explanation:
First find the rocket's final position and velocity during the first phase in the y direction.
Given:
v₀ = 75 sin 53° m/s
t = 25 s
a = 25 sin 53° m/s²
Find: Δy and v
Δy = v₀ t + ½ at²
Δy = (75 sin 53° m/s) (25 s) + ½ (25 sin 53° m/s²) (25 s)²
Δy = 7736.8 m
v = at + v₀
v = (25 sin 53° m/s²) (25 s) + (75 sin 53° m/s)
v = 559.0 m/s
Next, find the final position of the rocket during the second phase (as a projectile).
Given:
v₀ = 559.0 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (559.0 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 15945.5 m
The total displacement is:
7736.8 m + 15945.5 m
23682.2 m
Rounded to two significant figures, the maximum altitude reached is 24,000 m.
