At point x = 0, the particle accelerates. Since there will be change of velocity at that point. The the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.
Given that a 2.0 kg particle moving along the z-axis experiences the force shown in a given figure.
Force is the product of mass and acceleration. While acceleration is the rate of change of velocity. Both the force and acceleration are vector quantities. They have both magnitude and direction.
If the particle's velocity is 3.0 m/s at x = 0 m, that mean that the particle experience change of velocity at point x = 0. Since the the force of the particle will change from negative sign to positive sign according to the given figure, we can therefore conclude that the particle will have a turning point at point x = 0.
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Answer:
F = 852 N
Explanation:
We apply Newton's second law to the trailer :
F = m*a Formula (1)
F : net force exerted by the truck on the trailer Newtons (N)
m : mass of the trailer in kilograms (kg)
a : acceleration of the trailer in meters over second square (m/s²)
Data
a=1.20 m/s² : acceleration of the trailer
m=710 kg : mass of the trailer
We replace data in the Formula (1) to calculate the net force exerted by the truck on the trailer
F = (710 kg)*(1.20 m/s²)
F = 852 N
Answer:
A) The green cars's velocity has the same magnitude as the blue car's velocity.
B) the difference about their velocity is the direction of the velocity which is 180° in the opposite directions.
Explanation:
Velocity is a vector quantity that has both magnitude and direction. The magnitude shows the size, and the direction shows the path the motion takes.
Both cars have the same magnitude but different directions. The difference in their direction is at a 180°angle.
