Answer:
The right options are:
a. The margin of error is 0.632
f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.
Question: select one or more correct options.
Step-by-step explanation:
The margin of error can be calculated from the upper and lower bounds of the confidence interval as:
E = (UB - LB)/2 = (13.232-11.968)/2 = 1.264/2
E = 0.632
As the confidence interval is calculated at 95% confidence, we are 95% confident that the true mean is within the calculated interval. So, there is a 95% chance that the true mean is between 11.968 and 13.232 minutes. Although we are not 100% confident (that's why Option d is false).
Also, this interval does not give us information about the sampling distribution (option e is false).
Answer:
3 inches
Step-by-step explanation:
if it is a square we know that both sides must be the same
A=LW
L=W
A=W^2
9=W^2
=3
W=3 L=3
You would round up 3465 to 3470 and round up 2716 to 2720, the difference would be 750
Answer:
$49
Step-by-step explanation:
I know this because
x/140 = 35/100
cross multiply
4900 divided by 100=
$49 dollars is the discount amount.
I hope this helped you!:)
Answer:
Part a) The volume of the air is ![V=7,794.78\ cm^{3}](https://tex.z-dn.net/?f=V%3D7%2C794.78%5C%20cm%5E%7B3%7D)
Part b) The volume of the plastic is ![V=386.45\ cm^{3}](https://tex.z-dn.net/?f=V%3D386.45%5C%20cm%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the sphere is equal to
![V=\frac{4}{3}\pi r^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E%7B3%7D)
step 1
Find the volume of the complete ball (air +plastic)
we have
------> the radius is half the diameter
substitute
![V=\frac{4}{3}\pi (12.5)^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%2812.5%29%5E%7B3%7D)
![V=8,181.23\ cm^{3}](https://tex.z-dn.net/?f=V%3D8%2C181.23%5C%20cm%5E%7B3%7D)
step 2
Find the volume of the air
we have that
The plastic is 2 mm thick
Convert to cm
2 mm=2/10=0.2 cm
so
The radius of the interior of the ball is
![r=12.5-0.2=12.3\ cm](https://tex.z-dn.net/?f=r%3D12.5-0.2%3D12.3%5C%20cm)
substitute
![V=\frac{4}{3}\pi (12.3)^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%2812.3%29%5E%7B3%7D)
-----> this is the volume of the air (interior of the ball)
step 3
Find the volume of the plastic
we know that
The volume of the plastic is equal to the volume of the complete ball minus the volume of the air
so
![8,181.23\ cm^{3}-7,794.78\ cm^{3}=386.45\ cm^{3}](https://tex.z-dn.net/?f=8%2C181.23%5C%20cm%5E%7B3%7D-7%2C794.78%5C%20cm%5E%7B3%7D%3D386.45%5C%20cm%5E%7B3%7D)