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Dovator [93]
2 years ago
10

PLEASE IM BEGGING U so hard to understand T_T

Mathematics
1 answer:
boyakko [2]2 years ago
3 0

Answer:

b^{2} +7b+7 with remainder 1

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Determine the length of the leg of a 45o – 45o – 90o triangle with a hypotenuse length of 15 inches. ( ANSWER NEEDS TO BE IN RED
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Answer:

The lenghts of both legs: \frac{15\sqrt{2}}{2}\ inches

Step-by-step explanation:

By definition, when a triangle has angles that measures 45°, 45° and 90°, its legs are congruent.

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sin(45\°)=\frac{leg}{15}\\\\leg=\frac{15}{\sqrt{2}}

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