Answer:
The probability that a randomly chosen person has measles antibodies in his/her blood if the new test is positive = 0.9796
Step-by-step explanation:
The event that someone tests positive = P(T)
The event that someone has antibodies = P(A)
The event that someone does not have antibodies = P(A')
The new test was positive when administered to 96% of those who have the antibodies.
This probability = P(T n A) = 0.96
The new test gave positive results in 2% of those who do not have them.
This probability = P(T n A') = 0.02
The probability that a randomly chosen person has measles antibodies in his/her blood if the new test is positive = P(A|T)
This conditional probability is given as
P(A|T) = P(T n A) ÷ P(T)
P(T) is given as
P(T) = P(T n A) + P(T n A') = 0.96 + 0.02 = 0.98
P(A|T) = P(T n A) ÷ P(T) = 0.96 ÷ 0.98 = 0.9796
Hope this Helps!!!
Domain: x is greater than or equal to 2 but is less than our equal to 7
range: y is greater than or equal to 6 but is less than or equal to 18
P=2l+2w
P=2(120)+2(90)
P=240+180
P=420
420 feet of fencing is needed.
Answer:
Option C and D that is y= tan x and y= cot x
Step-by-step explanation:
The range is the values of y means the values that y can take in a function:
So, range of tan x and cot x are all real numbers.
Period of tan x is
Period of cot x is
Option A and B that is secx and csc x are discarded
Answer: 4/15
Step-by-step explanation:
-1/3 - -3/5
Two negative signs become positive so it's
-1/3+3/5
Taking the LCM as 15,
-1/3= -5/15
3/5= 9/15
-5/15 + 9/15
= (-5+9)/15
= (9-5)/15 ( just changing the order without changing the sign)
= 4/15
This is the simplest form
(If you need it in decimal form is 0.26666... or 0.267)
Hope it helps