The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.
Answer:
2×2×5×5
Step-by-step explanation:
1st of all they are prime factors
if multiplied give us 100
Answer:
x = 18.5
Step-by-step explanation:
Multiply 5 and 3.7.
Which equals 18.5.
Check: 18.5 / 3.7 = 5.√
<span>Let the height of tree be denoted as AB and the shadow cast by the tree be BE. ABE is the triangle formed the tree, rays and the ground. Let the height of the person be CD and the length of his shadow be DE. CDE is the triangle formed by the person, rays and the ground.
We have two triangles. Both the person and the tree stand vertically over the horizontal ground, therefore they make 90 degrees with the ground. The angle formed at the ground is the same for the both the triangles. Therefore, by AA similarity the two triangles are similar.
We know that if two triangles are similar, then their sides are proportional.
Therefore,
AB/CD =BE/DE
AB/6 = 143/11
AB= (143/11) *6
AB = 78 ft.</span>