In order to write the Aluminium electron configuration we first need to know the number of electrons for the Al atom (there are 13 electrons). When we write the configuration we'll put all 13 electrons in orbitals around the nucleus of the Aluminium atom.
Answer:
I'm going to call the length of the bracelet the number of times you have to add to get back to the first bead. This is the same as the number of beads, except in one case:
The shortest bracelet has length 1 and starts with (0,0). If you add one time, you get back to the first 0. But the bracelet has two beads. (Every bracelet has to have at least two beads to start.) The next shortest bracelet starts with (0,5), and has length 3: 0 5 5.
There is a bracelet of length 4 that starts with (2,6) (the first example on the main page):
2 6 8 4
There is a bracelet of length 12 that starts with (1,3) (the second example on the main page):
1 3 4 7 1 8 9 7 6 3 9 2
There is a bracelet of length 20 that starts with (0,4)
0 4 4 8 2 0 2 2 4 6 0 6 6 2 8 0 8 8 6 4
There is a bracelet of length 60 that starts with (0,1)
Explanation:
The orbital for fluorine is 1s 2s 2p. All of the boxes should be filled COMPLETELY until you can't no more. How do you know if you can't anymore? By the <u>atomic number</u> of the element. The atomic number for fluorine is 9. So, you keep adding arrows starting from the first box all the way to the last until you have reached the atomic number, in this case, 9.
Answer:
Something that breaks with little force against it.
The answer is D. CaCl2 and H2O