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Artist 52 [7]
1 year ago
6

The molar heat of the vaporization of ammonia i 23. 3 kJ/mol. What i the molar

Chemistry
1 answer:
dimaraw [331]1 year ago
3 0

The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condensation of ammonia is - 23.3 kJ/mol.

The molar heat of condensation is the opposite of the molar heat of vaporization. The molar heat of vaporization of ammonia is given :

ΔH evaporation = - ΔH condensation

Therefore the molar heat of  condensation of ammonia is given by:

ΔH condensation = - 23.3 kJ / mol

That's right. The molar heat  of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condesation of ammonia is - 23.3 kJ/mol.

Learn more about heat of condensation at

brainly.com/question/14380051

#SPJ4

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Which of the following is most likely to be covalent?<br> MgO <br> CO <br> CaO <br> BaO
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??

Explanation:

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Read 2 more answers
3 points
vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

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<em><u>I </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this </u></em><em><u>is </u></em><em><u>helpful</u></em>

8 0
3 years ago
How many moles of oxygen are needed for the complete combustion of 29.2 grams of acetylene?
podryga [215]

Moles of Oxygen= 2.8075 moles

<h3>Further explanation</h3>

Given

29.2 grams of acetylene

Required

moles of Oxygen

Solution

Reaction(Combustion of Acetylene) :

2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)

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