Answer:
i think it is all atoms of all elements are exactly alike and have the same mass
Explanation:
Concentration of vinegar sample of 28mL which requires 21. 5 ml of 0.550 M NaOH to reach the endpoint in a titration is 0.42M.
<h3>How do we calculate the concentration of Vinegar?</h3>
Concentration of vinegar in the titration method will be used by using the below equation:
M₁V₁ = M₂V₂,
- M₁ & V₁ are the molarity and volume of acetic acid.
- M₂ & V₂ are the molarity and volume of vinegar sample.
By putting values on above equation from the question, we get
M₂ = (0.55M)(21.5mL) / (28mL) = 0.42 M
Hence, required concentration of vinegar is 0.42M.
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Answer:
The first row fits in period 2
The second row fits in period 3
Explanation:
Elements arranged vertically in the periodic table in groups that share similar chemical properties.
Elements are also organized horizontally in rows or periods
The length of each period is determined by the number of electrons that can occupy the sublevels being filled in that period.
Answer:- 12.7%
Solution:- It says, ammonium phosphate is 60.9%. It means if we assume 100 g of the sample then there is 60.9 g ammonium phosphate in it.
Formula of ammonium phosphate is
and it's molecular weight is 149 grams per mol. There is only one P in the formula and so the mass of P in 149 g of ammonium phosphate is 31 g(atomic mass of P).
Now, we could use the proportions to find out the mass percentage of P in the sample.
31 g P is present in 149 g of ammonium phosphate, how many grams of P would be present in 60.9 g of ammonium phosphate. Let's set the proportions as:



This 12.7 g of phosphorous is present in 100 g of the sample means there is 12.7% phosphorous in the sample.
Hi, Again!
The answer to the drop downs are
•Increase
•Decreases
• 1:1
•5.9
Hope this helps !