One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin c, c6h8o6). given that one cup
1 answer:
The question is incomplete. Complete question is read as:
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
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Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.
Now, Molarity = </span>
=
<span> = 0.002995 mol/dm3
Answer: Molarity of solution = </span>0.002995 mol/dm3<span>
</span>
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
..........................................................................................................................
Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.
Now, Molarity = </span>
=
<span> = 0.002995 mol/dm3
Answer: Molarity of solution = </span>0.002995 mol/dm3<span>
</span>
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Answer : The concentration of A after 80 min is, 0.100 M
Explanation :
Half-life = 20 min
First we have to calculate the rate constant, we use the formula :
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
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a - x = amount left after decay process = ?
Now put all the given values in above equation, we get
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