Based on the given parameters, the value of the function h(-1) is -1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(-1)
This means that t = -1
So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1
h(-1) =-(-1)^2 + (-1) + 1
Evaluate the exponent
h(-1) =-1 - 1 + 1
Evaluate the like terms
h(-1) = -1
Hence, the value of the function h(-1) is -1
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(−1)
The two consecutive integers would be 10 and 12. Not 100% sure though.
Given that Z is the centroid of a triangle RST. This means that Z is the point of intersection of the three medians of the triangle.
So,W is the midpoint of RSV is the midpoint of RTWe are given that:RV = 4x + 3 and VT = 2x + 9
Since V is the midpoint, then:RV = VT4x + 3 = 2x + 94x - 2x = 9 - 32x = 6x = 3
Now put the value of x in WS = 5x-1WS = 5x-1WS = 5(3) - 1 WS = 15 - 1 = 14WS = 14
Since W is the midpoint of RS, therefore RW = WSand WS = 14Therefore:
RW = 14
I think it’s A.6.3
Sorry if I’m wrong but I’m pretty sure it’s that.
Since you subtract 16 from the y value, P is (-2, 6), and the y value comes second (meaning that it's 6), we get 6-16=-10
