Ted likes to run long distances. He can run 20 km 95 minutes. He wants to know how many kilometers (k) he will go if he runs at
2 answers:
Answer:
Ted can run 60 km in 285 minutes.
Step-by-step explanation:
Consider the provided information.
Ted can run 20 km in 95 minutes.
Now, calculate how much he can run in 1 minute.
Now, calculate the distance cover by him if he runs at the same pace for 285 minutes.
Multiply both the sides of the above equation with 285.
Hence, ted can run 60 km in 285 minutes.
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Answer:
If we compare the p value and the significance level given for example we see that
so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.
Step-by-step explanation:
1) Data given and notation
represent the sample mean
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Calculate the P-value
First we need to calculate the degrees of freedom given by:
Since is a one-side upper test the p value would be:
Conclusion
If we compare the p value and the significance level given for example we see that
so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.