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Tomtit [17]
3 years ago
8

Compute show all of your work: 8X4-4/2+1

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0
8*4-4/2+1    
32-4/2+1
32-2+1
=31 answer 
So, the answer to this question is 31

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Solve the system.<br> x + y - z = 17<br> y +z = 1<br> z = -3
Anna35 [415]

Answer:

(10, 4, -3)

Step-by-step explanation:

z = -3

y + z = 1

y - 3 = 1

y = 4

x + y - z = 17

x + 4 - -3 = 17

x + 4 + 3 = 17

x + 7 = 17

x = 10

(10, 4, -3)

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Step-by-step explanation:

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3 years ago
In the literal equation below, what do C and F represent?
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3 years ago
What's the word called for when people don't believe in ghosts or any type of things , there was a specific word !
Tom [10]

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Skeptics

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3 0
2 years ago
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where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
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