Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
It's moderate positive because when the number is closer to zero the weaker it is and the closer to one its stronger so since 0.44 is in more in the middle it moderate and since there is no negative sign which is - then it moderate positive. Btw I took the test and it was right.
Answer:
Its A
Step-by-step explanation:
4/5 - 0.5 Convert the fraction to a decimal:-
= 0.8 - 0.5
= 0.3
30 minutes / 3 miles = 10 minutes for 1 mile
7 miles * 10 minutes per mile = 70 minutes total to run 7 miles
