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AlekseyPX
3 years ago
13

PLZ ANSWER SCREENSHOT

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

2012, 2011, 2009, 2008, 2010

Step-by-step explanation:

Before we can answer this question we need to understand what the information on the table shows.

This table shows how far away from the average rainfall each year was. When a number has a + in front of it, it was above average, which means there was more rain. If there is a - in front of it, it was below average, which means there was less rain.

From this, we can see that the largest negative numbers will be the least amount of rain and the largest positive numbers will be the greatest amount of rain.

This means that the order would be : -4.46, -4.38, -2.68, +6.57, +12.26

And in years this would be : 2012, 2011, 2009, 2008, 2010

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=======================================================

Explanation:

f(x) is continuous when x >= 1. The only discontinuity for f(x) is when x = 0, but 0 is not part of this interval.

f(x) is positive for any valid x value in the domain since x^6 is always positive. In general, x^n is positive for all x when n is any even number.

f(x) is decreasing. You can see this through a table of values or through a graph. For anything in the form 1/(x^k), it will be a decreasing function because x^k gets larger, so 1/(x^k) gets smaller, when x goes to infinity.

--------------------

The conditions to use the integral test have been met. So we have to see if \displaystyle \int_1^{\infty}f(x)dx converges or not.

Let's integrate and find out

\displaystyle \int \frac{1}{x^6} dx = \int x^{-6} dx\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{1+(-6)}x^{-6+1}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{-5}x^{-5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5}*\frac{1}{x^5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5x^5}+C\\\\

So we have

\displaystyle g(x) = \int f(x) dx\\\\\\\displaystyle g(x) = \int \frac{1}{x^6} dx\\\\\\\displaystyle g(x) = -\frac{1}{5x^5}+C\\\\\\

Meaning that,

\displaystyle \int_{a}^{b} f(x) dx = g(b)-g(a)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = \left(-\frac{1}{5b^5}+C\right)-\left(-\frac{1}{5a^5}+C\right)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = -\frac{1}{5b^5}+\frac{1}{5a^5}\\\\\\

If we plug in a = 1 and apply the limit as b approaches positive infinity, then the expression -\frac{1}{5b^5}+\frac{1}{5a^5} will turn into \frac{1}{5}

Therefore,

\displaystyle \int_{1}^{\infty} \frac{1}{x^6} dx = \frac{1}{5}\\\\\\

Because this integral converges, this means the series \displaystyle \sum_{n=1}^{\infty}\frac{1}{n^6} also converges as well by the integral test.

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Step-by-step explanation:

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Answer:

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