A 1100-N crate rests on the floor.

Physics

1 answer:

Tom [10]2 years ago

6 0

(a) The work done in moving the crate along the floor is 7,050 J.

(b) The work done in moving the crate vertically is 0 J.

<h3>Work done in moving the crate horizontally</h3>

W = Fdcosθ

where;

F is total force to be applied
d is displacement of the crate
θ is the horizontal angle = 0

W = (1100 + 310) x 5

W = 7,050 J

<h3>Work done in moving the crate vertically</h3>

W = Fd cos(90)

W = 0

Thus, the work done in moving the crate along the floor is 7,050 J.

the work done in moving the crate vertically is 0 J.

Learn more about work done here: brainly.com/question/8119756

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<u>Net Force And Acceleration </u>

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The components of the first force are

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