Question

14) A barking dog delivers about 1 mW of power, which is assumed to be uniformly distributed in all directions. What is the intensity level at a distance 5.00 m from the dog?

Answer 1

Answer:

Intensity of sound is given as

$I = 3.18 \times 10^{-6} W/m^2$

Explanation:

As we know that the intensity of the sound is defined as power received per unit area

So here we know that dog delivers total power

P = 1 mW

now it delivers it into spherical area of radius r = 5 m

now we have

$I = \frac{P}{4\pi r^2}$

so we have

$I = \frac{1\times 10^{-3}}{4\pi(5^2)}$

$I = 3.18 \times 10^{-6} W/m^2$