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alekssr [168]
3 years ago
11

Find the slope and the y-intercept of the equation y − 3(x − 1) = 0.

Mathematics
2 answers:
nekit [7.7K]3 years ago
6 0
In this problem, we need to isolate the y variable. To do so, we can first distribute the -3 into the (x-1) to get y - 3x + 1 = 0.
Then, we can add 3x - 1 to both sides of the equation, making it:
y = 3x - 1
This is a linear equation in the form of y = mx + b. The m, 3 in this equation, is the slope. The b, -1 in this equation, is the y-intercept.
The slope is 3.
The y-intercept is -1.
Nikolay [14]3 years ago
3 0
<span>y − 3(x − 1) = 0.
y - 3x + 3 = 0
y = 3x - 3

slope m = 3
y-intercept (0, -3)</span>
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Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

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1 year ago
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