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AveGali [126]
3 years ago
6

How do you explain HOW TO GET 10 x 2 - 3^2 + 4/2 -7= 6

Mathematics
1 answer:
ANTONII [103]3 years ago
8 0

Answer:

 ((x - (2x - 3)/(3x - 2))/(3x + 4)

and its fractional equivalent

       2x - 3

   x - ------

       3x - 2

   ----------

     3x + 4

it is easier to see the relation between the various parts, and how it

might be simplified, when you see it in the latter form. Notice that I

didn't have to use parentheses at all; that's because the bar serves

the double purpose of indicating division and of separating the

divisor from the dividend. In fact, this usage derives in part from an

old use of the bar (called a vinculum) to do what we usually do with

parentheses today, by putting a bar above any group of symbols that

are to be kept together:

Step-by-step explanation:

if wrong report me

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adoni [48]

Answer:

<em>Graph below</em>

Step-by-step explanation:

<u>Transformations</u>

Triangle ABC has coordinates A=(-4,2) B=(-2,6) C=(3,2)

We'll use the transformation (x,y) -> (2x, y+3) to map it to the triangle A'B'C'. Let's calculate the coordinates:

A'=(-8,5)

B'=(-4,9)

C'=(6,5)

The image below shows both triangles in the same grid

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3 years ago
A train is carrying 1,425 passengers. Each of the train’s cars can hold 30 passengers. How many train cars are needed to hold al
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The train needs 48 carts in total
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3 years ago
Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0
3 years ago
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I’m not quite sure but i need to help someone
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A system of equations is shown below. Find the solution by using substitution.
ASHA 777 [7]

Answer:

a) (-2, 0)

Step-by-step explanation:

x + 2 = 3x + 6

-3x - 3x

___________

−2x + 2 = 6

- 2 - 2

_________

4 = −2x

_ ___

−2 −2

-2 = x [Plug this back into both equations above to get the y-coordinate of 0]; 0 = y

I am joyous to assist you anytime.

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3 years ago
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