What is two thirds equal to

Determine whether the given set S is a subspace of the vector space V.A. V is the vector space of all real-valued functions defi

Nataly [62]

Answer:

Check the explanation

Step-by-step explanation:

kindly check the attached image below to Determine whether the given set S is a subspace of the vector space (which is contained within a different vector space. So all the subspace is a kind of vector space in their own way, although it is also defined relative to some of the other larger vector space. The linear subspace is more often than not simply called a subspace whenever the situation serves to differentiate it from other types of subspaces.) V.A

5 0

3 years ago

solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars

Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

Every x has only one value of y

x appears once in ordered pairs

Examples:

The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)

The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)

The domain is the set of values of x

The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0

2 years ago

The table represents an exponential function.

Stels [109]

The exponential function is given in the form

$y= a (b)^{x}$

where a is the initial value and b is the multiplicative rate of change

So lets plug the first two values of the table in this function , we get

$2= a(b)^1$

or

$2= ab............................(eqn 1)$

Now plug second

$2/5 = a(b)^2 .............................( eqn2)$

Divide equation 2 by equation 1

$\frac{2=ab}{\frac{2}{5}=ab^2}$

On simplifying we get

$5= \frac{1}{b}$

or

$b=\frac{1}{5}$

So the multiplicative rate of change of the function is

$a) \frac{1}{5}$

8 0

3 years ago

Read 2 more answers

What is the range of the function shown in the graph below? answer type: interval, all real values except one, all real values e

Sever21 [200]

Answer:

Hey there!

The range is the possible y values, so the range of this graph would be all real numbers less than or equal to -6.

Let me know if this helps :)

6 0

3 years ago

Read 2 more answers

The skittles jar has a radius of 3.5 cm and a height of 11.5 cm. using the two given boxes for reference what would be a good es

Bond [772]

C) 1059 skittles

Step-by-step explanation:

We know that the first container held 192 skittles. Knowing the dimension of the container we can calculate the volume of 192 skittles:

Volume of 192 skittles = 5 × 4 × 4 = 80 cm³

Volume of 1 skittle = 80 / 192 = 0.42 cm³

We also know that the second container held 258 skittles. Knowing the dimension of the container we can calculate the volume of 258 skittles:

Volume of 258 skittles = 12 × 3 × 3 = 108 cm³

Volume of 1 skittle = 108 / 258 = 0.42 cm³

We found that the volume of 1 skittle is equal to 0.42 cm³. Now we calculate the volume of the skittles jar:

volume of cylinder = π × radius² × height

volume of skittles jar = 3.14 × 3.5² × 11.5 = 442 cm³

Now we can calculate the number of skittles in the jar:

number of skittles in the jar = volume of the jar / skittle volume

number of skittles in the jar = 442 / 0.42 = 1052 which is close the C) 1059

Learn more about:

volume of cylinder

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7 0

3 years ago