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Masteriza [31]
3 years ago
12

Convert 490 square meters to square dekameters please show work, if you can't thats okay

Mathematics
2 answers:
lisov135 [29]3 years ago
7 0
1 square meter is 0.01 decameter in the table
So, 490 X 0.01 = 4.9 decameters

Hope I helped :)
Savatey [412]3 years ago
5 0
The answer will be 4.9. =) 

Since we know 1 metre is 0.01 dekametres, we can use this to answer the question!

We simply multiply 490 by 0.01. =)
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Deffense [45]

Answer:

work is shown and pictured

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3 years ago
The minimum and maximum temperature on a cold day can be modeled by the equation 2[x-6]+14=38 What are the min and max temperatu
SashulF [63]
Here are the steps to calculating the given equation:

Distribute 2 to x and 6: 2x-12+14=38
Group like terms: 2x+(-12+14)=38
Combine like terms: 2x+2=38
Subtract number on 'x' side: 2x+2-2=38-2
Simplify: 2x=36
Divide: 2x/2=36/2
Simplify: x=18
Label with correct terms: 
I cannot do this because you did not provide sufficient information, I would need to know what the difference between the two, or if 'x' stood for one particular temperature. Hope that helped enough with what you provided.
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2 years ago
Read 2 more answers
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slamgirl [31]

Answer:

(4, 0)

Step-by-step explanation:

The circumference of a circle is 2 \pi r where <em>r</em> is the radius.

In this case, 2 \pi r = 10 \pi.  Divide both sides of the equation by 2\pi to get

r=5

The center of the circle is on the <em>x</em>-axis, so the intercepts are 5 units to the left of the center and 5 units to the right of the center.  The two intercepts are (-1-5, 0) and (-1+5, 0).  The point that is on the positive <em>x</em>-axis is (4, 0).

See attached image.

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1 year ago
Pls helpppp pls its due by 9
Vsevolod [243]

Answer:

25% of 140 is 35

Step-by-step explanation:

that's the answer for #3

6 0
2 years ago
Can someone please help? Only answer the question correctly, please!<br><br> Question is down below.
DIA [1.3K]

Answer:

<h2>{6y}^{2}</h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

\frac{1}{ {6y}^{ - 2}  }

<em><u>Since</u></em><em><u>,</u></em>

{x}^{ab}  =  {( {x}^{a} )}^{b}

<em><u>Hence</u></em><em><u>,</u></em>

=  \frac{1}{ {( {6y}^{2} )}^{ - 1} }

<em><u>Since</u></em><em><u>,</u></em>

\frac{1}{ {x}^{ - 1} }  = x

<em><u>Hence</u></em><em><u>,</u></em>

=  {6y}^{2} (ans)

7 0
2 years ago
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