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joja [24]
1 year ago
6

Becca's car engine has a capacity of 3.6 quarts and

Mathematics
1 answer:
Pie1 year ago
4 0

Becca needs approximately 5 bottles of engine oil to completely fill her car engine.

<h3>How to determine the number of bottles of engine oil?</h3>

Since Becca's car engine has a capacity of 3.6 quarts and contains 1.2 quarts of engine oil, the remaining space left in her car engine is given by:

Space = 3.6 - 1.2

Space = 2.4 quarts.

By applying direct proportion, we have:

1 bottle = 0.5 quart.

x bottles = 2.4 quarts.

Cross-multiplying, we have:

0.5x = 2.4

x = 2.4/0.5

x = 4.8 ≈ 5 bottles.

Read more on direct proportion here: brainly.com/question/1266676

#SPJ1

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Answer:

  Ben's

Step-by-step explanation:

If E is the amount of energy that each full set of panels produces, then ...

  3 of Ismael's 5 panels produce 3/5E

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We can compare these fractions when they have a common denominator.

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  4/6E = 20/30E . . .  energy from Ben's panels

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5 0
3 years ago
2. In the figure, is an exterior angle to . complete sentences
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What is the slope between the points (3, 5) and (-2, -4)
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How do you find the Median Absolute and Deviation
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Answer:

Calculate Mean Absolute Deviation (M.A.D)

Step-by-step explanation:

To find the mean absolute deviation of the data, start by finding the mean of the data set.Find the sum of the data values, and divide the sum by the number of data values.Find the absolute value of the difference between each data value and the mean: |data value – mean|.

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In a experiment, the probability that event A occurs is 5/9, the probability that event B occurs is 5/7, and the probability tha
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Answer:

52.5% probability that A occurs given B occurs

Step-by-step explanation:

Suppose we have two events, A and B, the conditional probability formula is:

P(A|B) = \frac{P(A \cap B)}{P(B)}

In which

P(A|B) is the probability of A happening given that B happened.

P(A \cap B) is the probability of both A and B happening.

P(B) is the probability of B happening.

In this problem, we have that:

P(A \cap B) = \frac{3}{8}, P(B) = \frac{5}{7}

So

P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{3}{8}}{\frac{5}{7}} = 0.525

52.5% probability that A occurs given B occurs

7 0
3 years ago
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