The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
Answer:
8xb + 456x
Step-by-step explanation:
8x(b + 456)
8xb + 456x
You multiply 8x by the numbers in the parenthesis. And you add the variables to the coefficents.
<em>I hope it helps! Have a great day!</em>
<em>Lilac~</em>
Answer:
Step-by-step explanation:
we know that
In the diagram
Equate
Two expressions for the perimeter of a square are:
4a
- a represents one side of the square
a + a + a + a
- a representa one side of the square
the first expression does not include any addition. But the two expressions are actually equivalent.
Yes it is an irrational number
