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pshichka [43]
3 years ago
13

An observer on the ground is x meters from the base of the launch pad of a rocket, which is at the same level as the observer. A

few seconds after the rocket takes off vertically, the observer sees its tip at an angle of q° from the horizontal. How far above the ground is the tip of the rocket at that instant? Assume that the ground is level.
a) x/ tan q
b) x/sin q
cx tan q
d) x cos q
Mathematics
1 answer:
Flauer [41]3 years ago
8 0
To illustrate the problem, refer to the following diagram, made with the ever-helpful notepad application:

  |\  |  \  |    \h|      \  |        \  |          \  |_____q\      x

Pretending as if that is a wonderfully-drawn triangle, we are given the distance x of the observer from the launch pad. The angle q is also stated, and is located in the diagram as shown. To look for the distance h of the tip of the rocket to the ground, we consider the following trigonometry function:

tan q = h/x

Since we are solving for h, we multiply both sides with x, giving us:

h = x * tan q

Among the choices, the correct answer is C.
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Fudgin [204]

Answer: The radius of the new water tower is approximately 21 ft^3

Step-by-step explanation:

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3 years ago
true or false: the points (6, 13), and (21, 33) and (99, 137) all lie on the same line. th equation of the lines is y + /3x + 5.
Phoenix [80]

Answer:

point A (6,13) lies on the equation.  True

given point  B(21,33) lies on the equation.  True

given point  C (99, 137) lies on the equation.  True

The equation that was given was  y = 4/3x + 5

Now,check the given equation for the given points.

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y = 4/3(6) + 5 = 4(2) + 5 = 8+5 = 13

y=13

the given point A (6,13) lies on the equation.

2)  B  (21,33)

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y=4/3(21) + 5 = 4(7) + 5=28+5=33

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the given point  B(21,33) lies on the equation.

3)  C (99, 137)

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y = 137

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2 years ago
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