Ask question

Ask question

All categories

2 years ago

15

WILL GIVE BRAINLIEST

1 answer:

vesna_86 [32]2 years ago

7 0

The simplified forms of the given expressions are

a. 32x

b. 0

c. -26t + 14x

d. 3t

<h3>Simplifying an expression </h3>

From the question, we are to simplify the given expressions by adding or subtracting

a. (10x) + (22x)

= 32x

b. (-6x) - (-6x)

= -6x + 6x

= 0

c. (-13t) + (14x) - (+13t)

= -13t + 14x - 13t

Collect like terms

= -13t -13t + 14x

= -26t + 14x

d. (-4t) + (+4t) - (-3t)

= -4t + 4t + 3t

= 3t

Hence, the simplified forms of the given expressions are

a. 32x

b. 0

c. -26t + 14x

d. 3t

Learn more on Simplifying an expression here: brainly.com/question/723406

#SPJ1

You might be interested in

Please help ASAP!!!!!!

N76 [4]

Step-by-step explanation:

To calculate the volume of a pyramid with a rectangular base, find the length and width of the base, then multiple those numbers together to determine the area of the base. Next, multiply the area of the base by the height of the pyramid. Take that result and divide it by 3 to calculate the pyramid's volume!

4 0

3 years ago

Which expression is the simplest form of -(2x + y) + 3(x - 4y)?

xenn [34]

Answer:

The answer is x - 13y

Step-by-step explanation:

6 0

3 years ago

Solve 2-18x-6=-7x+3+10x

Temka [501]

Answer:

x= -1/3

Step-by-step explanation:

First, we can combine like terms on each side:

-4-18x=3x+3

Then, we move all of the variables onto one side and the constant onto the other:

-18x-3x=3+4

-21x=7

x=-7/21

x= -1/3

Hope this helps!

7 0

3 years ago

Read 2 more answers

The square root of 9x^4/36 simplified

Serggg [28]

Step-by-step explanation:

$\sqrt{ \frac{9 {x}^{4} }{36} } \\ \\ = \sqrt{ \frac{ {x}^{4} }{4} } \\ \\ = \frac{ {x}^{2} }{2}$

6 0

3 years ago

Suppose that x is a binomial random variable with n=5, p=. 3,and q=. 7.1. Write the binomial formula for this situation and list

Radda [10]

Answer:

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: Any from 0 to 5.

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 5, p = 0.3, q = 1 - p = 0.7$

So

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: 5 trials, so any value from 0 to 5.

For each value of x calculate p(☓ =x)

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

8 0

3 years ago