Answer:
Part 1) AJ drawn the parabola opening upwards, instead of drawing it opening downwards
Part 2) see the explanation
Step-by-step explanation:
Part 1) What mistake did AJ make in the graph?
we have

This is the equation of a vertical parabola written in vertex form
The parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The vertex is the point (-2,-1)
therefore
AJ drawn the parabola opening upwards, instead of drawing it opening downwards
Part 2) Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?
take the values x=-4 and x=4
For x=-4
substitute the value of x in the quadratic equation

For x=4
substitute the value of x in the quadratic equation

According to AJ's graph for the value of x=-4 the function should be positive, however it is negative and for the value of x=4 the function should be positive and the function is negative
therefore
AJ made a mistake in the graph
Answer:
B. 8
Step-by-step explanation:
By evaluate, they mean substitute in the values and solve.
x + 3y - n
= 10 + 3(2) - n
= 10 + 6 - 8
= 8
Please lmk if you have questions.
Answer: Number of bags of 8. = 33
Number of bags of 10. = 31
Step-by-step explanation:
Let x = Number of bags of 8.
y = Number of bags of 10.
As per given.
(i)
(ii)
Put value of x from (ii) in (i)
Put this in (i), x= 31+2=33
Hence,
Number of bags of 8. = 33
Number of bags of 10. = 31
Answer:
The picture has a pattern. The pattern in this picture is that each time 4 corners are added. You can also look at this as it adds 4 each time or as the equation. Y=5+4x. Y being The amount of cubes in the equation