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OlgaM077 [116]
2 years ago
13

Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure bet

ween the locations. Diffusion occurs until ___________
Chemistry
1 answer:
yawa3891 [41]2 years ago
8 0

Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

<h3>What is the gas exchange in bloodstream?</h3>

The gas exchange refers to the process by which oxygen is absorbed by red blood cells and carbon dioxide is removed through the respiratory system.

The process of gas exchange is carried out due to the differential diffusion rates of gases in the bloodstream (O2 and CO2), which facilitates the transference of these gases.

In conclusion, each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

Learn more about gas exchange in bloodstream here:

brainly.com/question/17920029

#SPJ1

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The equation for density, d, is
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3 years ago
What is the most mass of (NH4)2CO3 (H=1,C=12,N=14,O=16
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Answer:

96.09 g/mol

Explanation:

You just need to first get the atomic weights of the elements involved. You can easily get these from your periodic table.

If you are going to do this properly, please use the weight with at least two decimal places for accuracy (e.g. 15.99 g/mol).

Also, please take note that I will be using the unit g/mol for all the weights. Thus,

Step 1

N = 14.01 g/mol

H = 1.008 g/mol

O = 16.00 g/mol

C = 12.01 g/mol

Since your compound is  

(

N

H

4

)

2

C

O

3

, you need to multiply the atomic weights by their subscripts. Therefore,

Step 2

N = 14.01 g/mol × 2 =

28.02 g/mol

H = 1.008 g/mol × (4×2) =

8.064 g/mol

 

O = 16.00 g/mol × 3 =

48.00 g/mol

C = 12.01 g/mol × 1 =

12.00 g/mol

To get the mass of the substance, we need to add all the weights from Step 2.

Step 3

molar mass of

(

NH

4

)

2

CO

3

=

(28.02 + 8.064 + 48.00 + 12.01) g/mol

=

96.09 g/mol

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