The final velocity of Bill after he catches the pillow is 4.44 m/s.
The given parameters:
- Mass of Bill, m1 = 77 kg
- Velocity of Bill, u1 = 2.6 m/s
- Mass of the pillow, m2 = 6.9 kg
- Initial velocity of the pillow, u2 = 25 m/s
<h3>What is conservation of linear momentum?</h3>
- The principle of conservation of linear momentum states that the total momentum of an isolated system is constant.
The final velocity of Bill is determined by applying the principle of conservation of linear momentum as follows;
Thus, the final velocity of Bill after he catches the pillow is 4.44 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
The correct answer is option D.
Explanation:
Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.
Rate of the reaction:
![R=-\frac{1}{1}\times \frac{d[NO_2]}{dt}=-\frac{1}{1}\times \frac{d[CO]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B1%7D%5Ctimes%20%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B1%7D%5Ctimes%20%5Cfrac%7Bd%5BCO%5D%7D%7Bdt%7D)
Rate of decrease in nitrogen dioxide concentration is equal to the rate of decrease in carbon monoxide.
Given rate expression of the reaction:
![R = k[NO2]^2[CO]](https://tex.z-dn.net/?f=R%20%3D%20k%5BNO2%5D%5E2%5BCO%5D)
Rate of the reaction on doubling concentration of nitrogen dioxide and carbon monoxide : R'
![R'=k(2\times [NO_2])^2(2\times [CO])=8\times k[NO2]^2[CO]=8R](https://tex.z-dn.net/?f=R%27%3Dk%282%5Ctimes%20%5BNO_2%5D%29%5E2%282%5Ctimes%20%5BCO%5D%29%3D8%5Ctimes%20k%5BNO2%5D%5E2%5BCO%5D%3D8R)
Doubling the concentrations of nitrogen dioxide and carbon monoxide simultaneously will increase the rate of the reaction by a factor of eight.
Hence, none of the given statements are true.
Answer:
so I will answer the first question: so if the waning gibbous happened on July 1 then you would expect the waxing crescent.
Density can be determined as:
d = m /V
whereas, m is mass of compound
v is volume
d = 700 /840 = 0.83 g /mL
Thus density is 0.83 g /mL
<span>the separation of air into oxygen, nitrogen, and other components?</span>
