Answer:
0.46 V
Explanation:
The emf for the cell is given by:
Eº cell = Eº oxidation + Eº reduction
From the given balanced chemical equation, we can deduce that Fe²⁺ has been oxidized to Fe³⁺, and O reduced from 0 to negative 2, according to the half cell reactions:
4Fe²⁺ ⇒ Fe³⁺ + 4e⁻ oxidation
O₂ + 4H⁺ + 4 e⁻ ⇒ 2 H₂O reduction
From reference tables for the standard reduction potential, we get
Eº red Fe³⁺ / Fe²⁺ Eºred = 0.77 V
Eº red O₂ / H₂O Eºred = 1.23 V
Now all we need to do is change the sign of Eº reduction for the species being oxidized ( Fe²⁺ ) and add it to Eº reduction O₂:
Eº cell = Eº oxidation + Eº reduction = - (0.77 V ) + 1.23 V = 0.46 V
Look out for angioedema (like hives but a deeper swelling due to an allergic reacrion), bleeding (such as intracranial, gastrointestinal and genitourinal hemorrhaging) and adverse reactions to drugs. Nausea, blood pressure spikes, severe headaches, acute hypertsnsion, etc are other signs of negative reacrions to iv t-pa as well.
Its the complete transfer of valence electrons between atoms
The evidence of the revival of Jansenism is the desire of ordinary people to connect themselves to what they saw as the direct work of God.
<h3>What is Jansenism?</h3>
Jansenism is a theological movement that is done with the mixing of Catholicism. It was active in France's kingdom.
Primarily throughout the seventeenth and eighteenth centuries, Jansenism flourished inside Roman Catholicism before being denounced as heresy in 1653 by Pope Innocent X.
Thus, the yearning of common people to participate in what they perceived as God's direct action is proof of the rebirth of Jansenism.
To learn more about Jansenism, refer to the link:
brainly.com/question/14563019
#SPJ4
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
