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SpyIntel [72]
3 years ago
8

Which passage from the Constitution describes the First Amendment right of

Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer: Congress shall make no law respecting an establishment

Step-by-step explanation:

You might be interested in
to find the perimeter of the rectangle you can see the formula P=21+2W. find the perimeter P of a rectangle whose length L is 10
Olin [163]

Answer:

rectangle, the distance around the outside of the rectangle is known as perimeter. A rectangle is 2-dimensional; however, perimeter is 1-dimensional and is measured in linear units such as feet or meter etc.

The perimeter of a rectangle is the total length of all the four sides.

Perimeter of rectangle = 2L + 2W.

Example 1: Rectangle has the length 13 cm and width 8 cm. solve for perimeter of rectangle.

Solution:

Given that:

Length (l) = 13 cm

Width (w) = 8 cm

Perimeter of the rectangle = 2(l + w) units

P = 2(13 + 8)

P = 2 (21)

P = 42

Thus, the perimeter of the rectangle is 42 cm.

Example 2: If a rectangle's length is 2x + 1 and its width is 2x – 1. If its area is 15 cm2, what are the rectangle's dimensions and what is its perimeter?

Solution:

We know that the dimensions of the rectangle in terms of x:

 l = 2x + 1

w = 2x – 1

Since the area of a rectangle is given by:

A = l * w

We can substitute the expressions for length and width into the equation for area in order to determine the value of x.

A = l * w

15 = (2x + 1) (2x -1)

15 = 4x2 – 1

16 = 4x2

x = ±2

 

 Note that the value of x must be positive and therefore in our case, the value of x is 2. And now we have:

l = 5 cm

w = 3 cm

Therefore, the dimensions are 5cm and 3cm.

Now, substituting these values in the formula for perimeter, we will get

P = 2l + 2w

P = 2(5)+2(3)

P = 10+6

P = 16 cm

Example 3: Find the area and the perimeter of a rectangle whose length is 24 m and width is 12m?

Solution:

Given that:

length = L = 24m

width = W = 12m

Area of a rectangle:

A = L × W

A = 24 × 12

A = 188 m2

Perimeter of a rectangle:

P = 2L + 2W

P = 2(24) + 2(12)

P = 48 + 24

P = 72 m

Example 4: Find the area and perimeter of a rectangle whose breadth is 4 cm and the height 3 cm.

Solution:

Area = b×h = 4×3 = 12 cm2.

Perimeter = 2(b) + 2(h) = 2(4) + 2(3) = 8 + 6 = 14.

Example 5: Calculate the perimeter of the rectangle whose length is 18cm and breadth 7cm

Solution:

Given that:

L = 18 cm

B = 7 cm

Perimeter of rectangle = 2(length + breadth)

P = 2 (L + B)

P = 2 (18 + 7)

P = 50 cm

Example 6: Find the perimeter of rectangle whose length is 6 inches and width is 4 inches.

Solution:

P = 2(L + B)

P = 2(6 + 4)

P = 20 in

Example 7: A boy walks 5 times around a park. If the size of the park is 100m by 50m, find the distance the boy has walked. If he walks 100m in 5 minutes, how long will it take for him in total?

Solution:

Given that:

Length = L = 100m

Width = W = 50m

Rounds = 5

Time per 100m = 5minutes.

Perimeter of the park:

P = 2 L + 2 W.

P = 2 × 100 + 2 × 50

P = 200 + 100

P = 300 m

Total distance walked = 5 × Perimeter of the park.

= 5 × 300

= 1500 meters

Total time taken = Total distance walked × time taken to walk 1m.

= 1500 × 5/100

= 75minutes or 1hr 15minutes

6 0
3 years ago
Can somebody please help me and how do you do this step by step and I need the formula for this please.
Ksivusya [100]

radius of ½ circle = d : 2

= 6in : 2 = 3in

Total area = Rectangle area + ½Circle area + Triangle area

= (l×w) + ½(π×r²) + (½×b×h)

= (10×6) + ½(π×3²) + (½ × (14-10) × 6)

= 60 + 14.14 + 12 = 86.14in

<h3 /><h3 /><h3>Answer : 86.14in</h3>

<em>See</em><em> </em><em>the</em><em> </em><em>bold</em><em> </em><em>one</em><em> </em><em>in</em><em> </em><em>line</em><em> </em><em>2</em><em> </em><em>of</em><em> </em><em>total</em><em> </em><em>area</em><em>,</em><em> </em><em>thats the</em><em> </em><em>formula</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>shape</em><em>.</em>

8 0
3 years ago
-ELIMINATION-- <br> 4x + 9y = 9 <br> x - 3y = -6
Troyanec [42]
The first on is this answer here

6 0
3 years ago
On a certain​ route, an airline carries 8000 passengers per​ month, each paying ​$70.A market survey indicates that for each​ $1
son4ous [18]

Answer:

The maximum revenue is $661,250.

Step-by-step explanation:

The total revenue (R) is the product between the number of passengers (N) and the price of each ticket (P), so the inicial revenue is:

R = N * P = 8000 * 70 = $560,000

For each 1$ increase in the ticket, the airline loses 50 passengers, so if we call "x" the increase in the ticket price, we have that the revenue equation will be:

R = (8000-50*x) * (70+x) = 560000 + 8000*x - 50*70*x -50x2

R = -50*x2 + 4500*x + 560000

The value of x that gives the maximum value of a quadratic function is found using the formula:

x = -b/2a

where a and b are coefficients of the quadratic equation (in our case, a = -50 and b = 4500)

So the value of x that gives the maximum revenue is:

x = -4500 / (-100) = 45

Using this value in the revenue equation, we have that the maximum R is:

R = -50*45^2 + 4500*45 + 560000 = $661,250

(To get this revenue, the ticket will cost 70+45 = $115 and there will be 8000-50*45 = 5750 passengers)

3 0
3 years ago
In a group of 60 students, 18 students take Algebra I, 20 students take Algebra II, and 10 students take both subjects. How many
frosja888 [35]
Your answer is B. 12. 

12 kids are unaccounted for after you subtract the kids that take A1, then A2, the both subjects. 
6 0
4 years ago
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